尽量沿着边走距离最短.化减后 C(n+1,k)+ n - k, 预处理阶乘,Lucas定理组合数取模 DP? Time Limit: 10000/3000 MS (Java/Others)    Memory Limit: 128000/128000 K (Java/Others) Total Submission(s): 1899    Accepted Submission(s): 633 Problem Description Figure 1 shows the Yang Hui Tri…

DP? Time Limit: 10000/3000 MS (Java/Others)    Memory Limit: 128000/128000 K (Java/Others)Total Submission(s): 1804    Accepted Submission(s): 595 Problem Description Figure 1 shows the Yang Hui Triangle. We number the row from top to bottom 0,1,2,…a…

开启DP之路 题目:http://acm.hdu.edu.cn/showproblem.php?pid=1069 描述一下: 就是给定N(N<=20)个方体,让你放置,求放置的最高高度,限制条件是:上面的物体的长度和宽度都小于下面物体. 觉得这道题目很经典: 于是贴下 .我们可以把一个方体看成六个,想到这里,然后求最高,方程很简单了 ,  if (a[j].x>a[i].x&&a[j].y>a[i].y)             ans=max(ans,a[j].h+a[…

DP? Problem Description Figure 1 shows the Yang Hui Triangle. We number the row from top to bottom 0,1,2,…and the column from left to right 0,1,2,….If using C(n,k) represents the number of row n, column k. The Yang Hui Triangle has a regular pattern…

最少拦截系统 Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 38985    Accepted Submission(s): 15293 Problem Description 某国为了防御敌国的导弹袭击,发展出一种导弹拦截系统.但是这种导弹拦截系统有一个缺陷:虽然它的第一发炮弹能够到达任意的高度,但是以后每一发炮弹都不能超过前一发的高…

Tickets Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 4393    Accepted Submission(s): 2236 Problem Description Jesus, what a great movie! Thousands of people are rushing to the cinema. However…

DP? Time Limit: 10000/3000 MS (Java/Others)    Memory Limit: 128000/128000 K (Java/Others)Total Submission(s): 3126    Accepted Submission(s): 978 Problem Description Input Input to the problem will consists of series of up to 100000 data sets. For e…

题意:在杨辉三角中让你从最上面到 第 n 行,第 m 列所经过的元素之和最小,只能斜向下或者直向下走. 析:很容易知道,如果 m 在n的左半部分,那么就先从 (n, m)向左,再直着向上,如果是在右半部分,那么就是先向左斜着走再向上.这样对应到, 然后化简得到的答案就是C(n+1, m) + n - m,和C(n+1, m+1) + m.然后用Lucsa 定理就好. 代码如下: #pragma comment(linker, "/STACK:1024000000,1024000000"…

[SinGuLaRiTy] Copyright (c) SinGuLaRiTy 2017.  All Rights Reserved. [CQBZOJ 2011] 计算系数 题目描述 给定一个多项式(ax + by)^k,请求出多项式展开后x^n y^m项的系数. 输入 共一行,包含 5 个整数,分别为a,b,k,n,m,每两个整数之间用一个空格隔开. 输出 输出共 1 行,包含一个整数,表示所求的系数,这个系数可能很大,输出对10007 取模后的结果. 样例数据 样例输入 样例输出 1 1 3…

题目传送门 /* 找规律/数位DP:我做的时候差一点做出来了,只是不知道最后的 is_one () http://www.cnblogs.com/crazyapple/p/3315436.html 数位DP:http://blog.csdn.net/libin56842/article/details/11580497 */ #include <cstdio> #include <iostream> #include <algorithm> #include <c…