POJ3666:Making the Grade——题解】的更多相关文章

POJ3666 Making the Grade 题意: 给定一个长度为n的序列A,构造一个长度为n的序列B,满足b非严格单调,并且最小化S=∑i=1N |Ai-Bi|,求出这个最小值S,1<=N<=2000,1<=Ai<=1e9. 引理:在满足S最小化的情况下,一定存在一种构造序列B的方案,使得B中的数值都在A中出现过. 由此,用一个数组b[i]初始化=a[i],然后对b从小到大排序,用f[i][j]表示完成了B中前i个数的构造,第i个数为b[j]时的最小的S.当第i个数等于b[…
http://poj.org/problem?id=3666 题目大意:给n个数,每次操作可使一个数+1或-1,求最小操作数使得序列不下降或不上升. —————————————————————— 思路:http://blog.csdn.net/luovilonia/article/details/44004041 因为我再讲什么也没什么好讲的了. 但是这人的代码是错的……请注意查找最长不上升和不下降所要减的值是不一样的. #include<cstdio> #include<cstring…
    正常的没想到的DP和玄学贪心. 题目描述 A straight dirt road connects two fields on FJ's farm, but it changes elevation more than FJ would like. His cows do not mind climbing up or down a single slope, but they are not fond of an alternating succession of hills and…
Making the Grade Time Limit: 1000MS   Memory Limit: 65536K Total Submissions:10187   Accepted: 4724 Description A straight dirt road connects two fields on FJ's farm, but it changes elevation more than FJ would like. His cows do not mind climbing up…
题目传送门 Making the Grade Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 9090   Accepted: 4253 Description A straight dirt road connects two fields on FJ's farm, but it changes elevation more than FJ would like. His cows do not mind climbi…
Description A straight dirt road connects two fields on FJ's farm, but it changes elevation more than FJ would like. His cows do not mind climbing up or down a single slope, but they are not fond of an alternating succession of hills and valleys. FJ…
0前言 感谢yxy童鞋的dp及暴力做法! 1 算法标签 优先队列.dp动态规划+滚动数组优化 2 题目难度 提高/提高+ CF rating:2300 3 题面 「POJ 3666」Making the Grade 路面修整 4 分析题面 4.1 简要描述 给出数列 \(A\), 求非严格单调不上升或单调不下降, 且\(S=\sum^N_{i=1}|A_i-B_i|\) 最小的序列\(B\),输出\(S\) 4.2 模型转换 输入\(N\), 然后输入\(N\)个数,求最小的改动这些数使之成非严…
题目大意:给你一个序列a[1....n],让你求一个序列b[1....n],满足 bi =a && bc,则最小的调整可以是把b变成c. 所以归纳可知上面结论成立. dp[i][j] 表示考虑前i个元素,最后元素为序列中 第j小元素的最优解,a[]数组存原始数组,b[]是对a从小到大排序. dp[i][j] = MIN(dp[i-1][k]) + abs(a[i]-b[j]), (0…
POJ2279 Mr. Young's Picture Permutations 题意 Language:Default Mr. Young's Picture Permutations Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 2513 Accepted: 960 Description Mr. Young wishes to take a picture of his class. The students will…
layout: post title: 「kuangbin带你飞」专题十二 基础DP author: "luowentaoaa" catalog: true tags: mathjax: true - kuangbin - 动态规划 传送门 A.HDU1024 Max Sum Plus Plus 题意 给你N个数,然后你分成M个不重叠部分,并且这M个不重叠部分的和最大. 思路 动态规划最大m字段和,dp数组,dp[i][j]表示以a[j]结尾的,i个字段的最大和 两种情况:1.第a[j…