Problem B Time Limit : 2000/1000ms (Java/Other)   Memory Limit : 65536/32768K (Java/Other) Total Submission(s) : 10   Accepted Submission(s) : 7 Font: Times New Roman | Verdana | Georgia Font Size: ← → Problem Description Eddy begins to like painting…

并查集+最小生成树 Eddy's picture Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 7669    Accepted Submission(s): 3882 Problem Description Eddy begins to like painting pictures recently ,he is sure of hi…

Eddy's picture Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 8797    Accepted Submission(s): 4476 Problem Description Eddy begins to like painting pictures recently ,he is sure of himself to b…

Eddy's picture Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 5797    Accepted Submission(s): 2913 Problem Description Eddy begins to like painting pictures recently ,he is sure of himself to…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1301 将结点的字符信息处理成点信息即可,代码如下: #include<bits/stdc++.h> using namespace std; typedef unsigned int ui; typedef long long ll; typedef unsigned long long ull; #define pf printf #define mem(a,b) memset(a,b,size…

http://acm.hdu.edu.cn/showproblem.php?pid=1162 最小生成树 #include<iostream> #include<stdio.h> #include<math.h> #include<string.h> #include<stdlib.h> using namespace std; ; struct stu{ int u; int v; double w; }p[N]; struct ln{ dou…

Eddy's picture 题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1162 ——每天在线,欢迎留言谈论. 题目大意: 给你N个点,求把这N个点连在一起的最短总距离. 思路: 假设每两两点之间都有路径,求最小生成树. AC代码:(Java) import java.util.Scanner; import java.math.*; public class Main { public static final int MAXN = 110;…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1162 [题目大意] 给你n个点的坐标,让你找到联通n个点的一种方法.保证联通的线路最短,典型的最小生成树问题. 方法一 . 通过不断找到最小的边来找到终于结果. Kruskal 算法 #include <iostream> #include <algorithm> #include <cstdio> #include <cmath> using namespac…

题目链接 Problem Description Eddy begins to like painting pictures recently ,he is sure of himself to become a painter.Every day Eddy draws pictures in his small room, and he usually puts out his newest pictures to let his friends appreciate. but the res…

链接: http://acm.hdu.edu.cn/showproblem.php?pid=1162 Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 8303    Accepted Submission(s): 4214 Problem Description Eddy begins to like painting pictures…

Eddy's picture Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 6339    Accepted Submission(s): 3179 Problem Description Eddy begins to like painting pictures recently ,he is sure of himself to b…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1162 Eddy's picture Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 6866    Accepted Submission(s): 3469 Problem Description Eddy begins to like p…

题目链接 Problem Description Eddy begins to like painting pictures recently ,he is sure of himself to become a painter.Every day Eddy draws pictures in his small room, and he usually puts out his newest pictures to let his friends appreciate. but the res…

Tree Time Limit: 6000/2000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 1954    Accepted Submission(s): 573 Problem Description There are N (2<=N<=600) cities,each has a value of happiness,we consider two cities…

畅通工程 http://acm.hdu.edu.cn/showproblem.php?pid=1863 1.Prim算法: Prim算法是由一个点(最初的集合)向外延伸,找到与集合相连权值最小的边, 然后把对应顶点拉到集合里,直到所有的顶点全部在集合里为止. Prim算法的演示如下: http://sjjp.tjuci.edu.cn/sjjg/DataStructure/DS/web/flashhtml/prim.htm #include <stdio.h> ; ; int map[MAXV]…

题目 #define _CRT_SECURE_NO_WARNINGS #include <stdio.h> #include<string.h> #include <malloc.h> #include<stdlib.h> #include<algorithm> #include<iostream> #include<math.h> using namespace std; #define M 110 #define in…

Fibonacci Tree Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 2915    Accepted Submission(s): 931 Problem Description Coach Pang is interested in Fibonacci numbers while Uncle Yang wants him to…

题目:http://acm.hdu.edu.cn/showproblem.php?pid=1233 可以用Kruskal来做,不过当图的边比较稠密的时候用prime会更快一些. AC代码:296MS #include <iostream> #include <cstring> #include <cstdio> using namespace std; const int inf=0xffffff; int dis[105],sum,n; int weight[105]…

题目: http://acm.hdu.edu.cn/showproblem.php?pid=1863 注意有可能出现无法生成树的情况. #include <iostream> #include <cstring> using namespace std; const int inf=0xffffff; int weight[105][105],n,m; int prime() { int sum=0; int pre[105]; int dis[105]; bool visit[1…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1233 思路分析:该问题为最小生成树问题,使用kruskal算法或者prim算法即可解决: 代码如下: #include <cstdio> #include <cstring> #include <iostream> #include <algorithm> using namespace std; + ; int u[MAX_N], v[MAX_N], w[MA…

畅通project再续 Problem Description 相信大家都听说一个"百岛湖"的地方吧,百岛湖的居民生活在不同的小岛中,当他们想去其它的小岛时都要通过划小船来实现. 如今政府决定大力发展百岛湖.发展首先要解决的问题当然是交通问题,政府决定实现百岛湖的全畅通! 经过考察小组RPRush对百岛湖的情况充分了解后.决定在符合条件的小岛间建上桥,所谓符合条件,就是2个小岛之间的距离不能小于10米,也不能大于1000米. 当然,为了节省资金.仅仅要求实现随意2个小岛之间有路通就可以…

Ice_cream's world III Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 1237    Accepted Submission(s): 408 Problem Description ice_cream's world becomes stronger and stronger; every road is buil…

HDOJ 题目分类 //分类不是绝对的 //"*" 表示好题,需要多次回味 //"?"表示结论是正确的,但还停留在模块阶 段,需要理解,证明. //简单题看到就可以敲的 1000:    入门用: 1001:    用高斯求和公式要防溢出 1004:1012: 1013:    对9取余好了 1017:1021: 1027:    用STL中的next_permutation() 1029:1032:1037:1039:1040:1056:1064:1065: 10…

HDOJ 题目分类 /* * 一:简单题 */ 1000:    入门用:1001:    用高斯求和公式要防溢出1004:1012:1013:    对9取余好了1017:1021:1027:    用STL中的next_permutation()1029:1032:1037:1039:1040:1056:1064:1065:1076:    闰年 1084:1085:1089,1090,1091,1092,1093,1094, 1095, 1096:全是A+B1108:1157:1196:1…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1162 意义:给出一些点,用线问使所有点直接或间接连通,需要多长: 思路:裸最小生成树: 法1: prim算法:MST(Minimum Spanning Tree,最小生成树)问题有两种通用的解法,Prim算法就是其中之一,它是从点的方面考虑构建一颗MST,大致思想是:设图G顶点集合为U,首先任意选择图G中的一点作为起始点a,将该点加入集合V,再从集合U-V中找到另一点b使得点b到V中任意一点的权值最…

全部函数通过杭电 1142,1162,1198,1213等题目测试. #include<iostream> #include<vector> #include<queue> #include<stack> #include<algorithm> #include<stdio.h> #include<stdlib.h> using namespace std; /* //函数集合声明下,方便查看 void Dijkstra(…

全部函数通过杭电 1142,1162,1198,1213等题目测试. #include<iostream> #include<vector> #include<queue> #include<stack> #include<algorithm> #include<stdio.h> #include<stdlib.h> using namespace std; /* //函数集合声明下,方便查看 void Dijkstra(…

Problem Description In 2100, since the sea level rise, most of the cities disappear. Though some survived cities are still connected with others, but most of them become disconnected. The government wants to build some roads to connect all of these c…

首先,贴上一个很好的讲解贴: http://www.wutianqi.com/?p=3012 HDOJ 1233 还是畅通工程 http://acm.hdu.edu.cn/showproblem.php?pid=1233 裸的Prim... #include<cstdio> #define MAXN 105 #define INF 0x3f3f3f3f int map[MAXN][MAXN]; int dist[MAXN]; int vis[MAXN]; int n,a,b,x,ans,tot…

Problem Description Coach Pang is interested in Fibonacci numbers while Uncle Yang wants him to do some research on Spanning Tree. So Coach Pang decides to solve the following problem:Consider a bidirectional graph G with N vertices and M edges. All…