题目大意 给你n个点的坐标和权值 问先在每一行选一个点再在每一列选一个没选过的点 求最大权值和 分析 可以想到将点转化为边,将两个坐标对应两个点 所以问题转化为选H+W个边 使得所有边的度都不为0 则最终这个图就会变为若干联通块 每个个联通块正好有一个环 我们将边权从大到小排序 然后并查集维护一下联通块信息和是否正好包含一个环即可 代码 #include<iostream> #include<cstdio> #include<cstring> #include<s…

容斥原理+状压 Card Collector Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 1940    Accepted Submission(s): 907Special Judge Problem Description In your childhood, do you crazy for collecting the bea…

http://acm.split.hdu.edu.cn/showproblem.php?pid=4336 Card Collector Special Judge Problem Description   In your childhood, do you crazy for collecting the beautiful cards in the snacks? They said that, for example, if you collect all the 108 people i…

Card Collector Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 3001    Accepted Submission(s): 1435Special Judge Problem Description In your childhood, do you crazy for collecting the beautiful…

Card Collector Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 1708 Accepted Submission(s): 780 Special Judge Problem Description In your childhood, do you crazy for collecting the beautiful cards…

Card Collector Problem Description In your childhood, do you crazy for collecting the beautiful cards in the snacks? They said that, for example, if you collect all the 108 people in the famous novel Water Margin, you will win an amazing award.  As a…

题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=4336 Card Collector Time Limit: 2000/1000 MS (Java/Others)Memory Limit: 32768/32768 K (Java/Others) 问题描述 In your childhood, do you crazy for collecting the beautiful cards in the snacks? They said that,…

[HDU4336]Card Collector(Min-Max容斥) 题面 Vjudge 题解 原来似乎写过一种状压的做法,然后空间复杂度很不优秀. 今天来补一种神奇的方法. 给定集合\(S\),设\(max\{S\}\)为\(S\)中的最大值,\(min\{S\}\)为集合\(S\)中的最小值. 那么我们可以得到: \(max\{S\}=\sum_{T\subseteq S}(-1)^{|T|+1}min\{T\}\) 证明的话,大概就是如果你钦定一个最小值,并且它强制出现, 如果枚举所有子集…

[HDU4336]Card Collector (动态规划,数学期望) 题面 Vjudge 题解 设\(f[i]\)表示状态\(i\)到达目标状态的期望 \(f[i]=(\sum f[j]*p[j]+1)/(\sum p[j])\) 直接枚举一下即可 #include<cstdio> int n; float f[1<<20],p[20]; int main() { while(scanf("%d",&n)!=EOF) { for(int i=0;i&l…

Card Collector Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 3407    Accepted Submission(s): 1665Special Judge Problem Description In your childhood, do you crazy for collecting the beautiful…