You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacent houses have security system connected and it will autom…

After robbing those houses on that street, the thief has found himself a new place for his thievery so that he will not get too much attention. This time, all houses at this place are arranged in a circle. That means the first house is the neighbor o…

The thief has found himself a new place for his thievery again. There is only one entrance to this area, called the "root." Besides the root, each house has one and only one parent house. After a tour, the smart thief realized that "all hou…

You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacent houses have security system connected and it will autom…

You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacent houses have security system connected and it will autom…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 递归 递归 + 记忆化 动态规划 优化动态规划空间 日期 [LeetCode] 题目地址:https://leetcode.com/problems/house-robber/ Total Accepted: 67398 Total Submissions: 196356 Difficulty: Easy 题目描述 You are a profess…

你是一个专业的强盗,计划抢劫沿街的房屋.每间房都藏有一定的现金,阻止你抢劫他们的唯一的制约因素就是相邻的房屋有保安系统连接,如果两间相邻的房屋在同一晚上被闯入,它会自动联系警方.给定一个代表每个房屋的金额的非负整数列表,确定你可以在没有提醒警方的情况下抢劫的最高金额. 详见:https://leetcode.com/problems/house-robber/description/ Java实现: class Solution { public int rob(int[] nums) { in…

Note: This is an extension of House Robber. After robbing those houses on that street, the thief has found himself a new place for his thievery so that he will not get too much attention. This time, all houses at this place are arranged in a circle. …

The thief has found himself a new place for his thievery again. There is only one entrance to this area, called the "root." Besides the root, each house has one and only one parent house. After a tour, the smart thief realized that "all hou…

Given an array A (index starts at 1) consisting of N integers: A1, A2, ..., AN and an integer B. The integer Bdenotes that from any place (suppose the index is i) in the array A, you can jump to any one of the place in the array A indexed i+1, i+2, ……

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 公众号:负雪明烛 本文关键词:刷题顺序,刷题路径,好题,top100,怎么刷题,Leetcode, 力扣,Python, C++, Java 大家好,相信很多朋友在刷题时,看到 LeetCode 的 2000 多道题目,有点手足无措,非常需要一个刷题的顺序和清单. 我整理了在 LeetCode(中文版)上点赞数前 100 的题目,这些的题目基本都在千赞以上,全部都是好题. 举个例子,1…

198. 打家劫舍 198. House Robber 题目描述 你是一个专业的小偷,计划偷窃沿街的房屋.每间房内都藏有一定的现金,影响你偷窃的唯一制约因素就是相邻的房屋装有相互连通的防盗系统,如果两间相邻的房屋在同一晚上被小偷闯入,系统会自动报警. 给定一个代表每个房屋存放金额的非负整数数组,计算你在不触动警报装置的情况下,能够偷窃到的最高金额. 每日一算法2019/5/8Day 5LeetCode198. House Robber 示例 1: 输入: [1,2,3,1] 输出: 4 解释:…

Leetcode之动态规划(DP)专题-198. 打家劫舍(House Robber) 你是一个专业的小偷,计划偷窃沿街的房屋.每间房内都藏有一定的现金,影响你偷窃的唯一制约因素就是相邻的房屋装有相互连通的防盗系统,如果两间相邻的房屋在同一晚上被小偷闯入,系统会自动报警. 给定一个代表每个房屋存放金额的非负整数数组,计算你在不触动警报装置的情况下,能够偷窃到的最高金额. 示例 1: 输入: [1,2,3,1] 输出: 4 解释: 偷窃 1 号房屋 (金额 = 1) ,然后偷窃 3 号房屋 (金额…

The thief has found himself a new place for his thievery again. There is only one entrance to this area, called the "root." Besides the root, each house has one and only one parent house. After a tour, the smart thief realized that "all hou…

Note: This is an extension of House Robber. After robbing those houses on that street, the thief has found himself a new place for his thievery so that he will not get too much attention. This time, all houses at this place are arranged in a circle.…

You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacent houses have security system connected and it will autom…

You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed. All houses at this place are arranged in a circle. That means the first house is the neighbor of the last one. Meanwhile, adjacent…

注意事项: 这是 打家劫舍 的延伸.在上次盗窃完一条街道之后,窃贼又转到了一个新的地方,这样他就不会引起太多注意.这一次,这个地方的所有房屋都围成一圈.这意味着第一个房子是最后一个是紧挨着的.同时,这些房屋的安全系统与上次那条街道的安全系统保持一致.给出一份代表每个房屋存放钱数的非负整数列表,确定你可以在不触动警报的情况下盗取的最高金额. 详见:https://leetcode.com/problems/house-robber-ii/description/ Java实现: class Sol…

The thief has found himself a new place for his thievery again. There is only one entrance to this area, called the "root." Besides the root, each house has one and only one parent house. After a tour, the smart thief realized that "all hou…

You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed. All houses at this place are arranged in a circle. That means the first house is the neighbor of the last one. Meanwhile, adjacent…

打家劫舍 题目描述 你是一个专业的小偷,计划偷窃沿街的房屋.每间房内都藏有一定的现金,影响你偷窃的唯一制约因素就是相邻的房屋装有相互连通的防盗系统,如果两间相邻的房屋在同一晚上被小偷闯入,系统会自动报警. 给定一个代表每个房屋存放金额的非负整数数组,计算你在不触动警报装置的情况下,能够偷窃到的最高金额. 示例 1: 输入: [1,2,3,1] 输出: 4 解释: 偷窃 1 号房屋 (金额 = 1) ,然后偷窃 3 号房屋 (金额 = 3).   偷窃到的最高金额 = 1 + 3 = 4 . 示例…

House Robber:不能相邻,求能获得的最大值 House Robber II:不能相邻且第一个和最后一个不能同时取,求能获得的最大值 House Robber III:二叉树下的不能相邻,求能获得的最大值 Paint House:用3种颜色,相邻的房屋不能用同一种颜色,求花费最小 Paint House II:用k种颜色,相邻的房屋不能用同一种颜色,求花费最小Paint Fence:用k种颜色,相邻的可以用同一种颜色,但不能超过连续的2个,求有多少种可能性 198. House Robb…

题目 You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacent houses have security system connected and it will au…

// Ref: https://segmentfault.com/a/1190000003811581// Ref: http://www.cnblogs.com/grandyang/p/4383632.html /*如果选择了抢劫上一个屋子,那么就不能抢劫当前的屋子,所以最大收益就是抢劫上一个屋子的收益如果选择抢劫当前屋子,就不能抢劫上一个屋子,所以最大收益是到上一个屋子的上一个屋子为止的最大收益,加上当前屋子里有的钱*/ public static long houseRobber(int[…

The thief has found himself a new place for his thievery again. There is only one entrance to this area, called the "root." Besides the root, each house has one and only one parent house. After a tour, the smart thief realized that "all hou…

小偷又发现一个新的可行窃的地点. 这个地区只有一个入口,称为“根”. 除了根部之外,每栋房子有且只有一个父房子. 一番侦察之后,聪明的小偷意识到“这个地方的所有房屋形成了一棵二叉树”. 如果两个直接相连的房子在同一天晚上被打劫,房屋将自动报警.在不触动警报的情况下,计算小偷一晚能盗取的最高金额.示例 1:     3    / \   2   3    \   \      3   1能盗取的最高金额 = 3 + 3 + 1 = 7.示例 2:     3    / \   4   5  / \…

题目描述 小偷又发现一个新的可行窃的地点. 这个地区只有一个入口,称为“根”. 除了根部之外,每栋房子有且只有一个父房子. 一番侦察之后,聪明的小偷意识到“这个地方的所有房屋形成了一棵二叉树”. 如果两个直接相连的房子在同一天晚上被打劫,房屋将自动报警. 在不触动警报的情况下,计算小偷一晚能盗取的最高金额. 示例 1: / \ 2 3 \ \ 3 1 能盗取的最高金额 = + + = 7. 示例 2: 3 / \ / \ \ 1 3 1 能盗取的最高金额 = + = 9. 解题思路 用后序遍历的…

Yet Another Source Code for LintCode Current Status : 232AC / 289ALL in Language C++, Up to date (2016-02-10) For more problems and solutions, you can see my LintCode repository. I'll keep updating for full summary and better solutions. See cnblogs t…

刷题备忘录,for bug-free leetcode 396. Rotate Function 题意: Given an array of integers A and let n to be its length. Assume Bk to be an array obtained by rotating the array A k positions clock-wise, we define a "rotation function" F on A as follow: F(k…

刷题备忘录,for bug-free 招行面试题--求无序数组最长连续序列的长度,这里连续指的是值连续--间隔为1,并不是数值的位置连续 问题: 给出一个未排序的整数数组,找出最长的连续元素序列的长度. 如: 给出[100, 4, 200, 1, 3, 2], 最长的连续元素序列是[1, 2, 3, 4].返回它的长度:4. 你的算法必须有O(n)的时间复杂度 . 解法: 初始思路 要找连续的元素,第一反应一般是先把数组排序.但悲剧的是题目中明确要求了O(n)的时间复杂度,要做一次排序,是不能达…