Description:     就是给你一个数,你可以把它自乘,也可以把他乘或除以任意一个造出过的数,问你最多经过多少次操作能变换成目标数 思路:这题真的不怎么会啊.n = 20000,每一层都有很多个扩展状态,裸宽搜会被T,启发式函数又设计不出来…… 看了一个Vjudge上的代码才知道这题怎么写. 就是每一个状态是由最多两个数转化而来的,所以可以把两个数看做一个状态. 用一个多元组$node(x,y,g,h)$表示状态,$x, y$分别表示两个数中的较大数和较小数,然后$g$表示转换成当前的…

Power Hungry Cows(POJ 1945) Description FJ的奶牛想要快速计算整数P的幂 (1 <= P <=20,000),它们需要你的帮助.因为计算极大数的幂,所以它们同一时间仅能使用2个存储器,每个存储器可记录某个结果值. 第一件工作是初始化存储器内的值一个为底数x, 另一个为1. 奶牛可以相乘或相除2个存储器中的值,并把结果存在其中某个存储器内,但所有存储的结果必须是整数. 例如, 如果他们想计算x^31, 一种计算方法是: WV1 WV2 开始: x 1 存储…

Power Hungry CowsTime Limit: 1000MS Memory Limit: 30000K Total Submissions: 4570 Accepted: 1120 Description FJ's cows would like to be able to compute integer powers P (1 <= P <= 20,000) of numbers very quickly, but need your help. Because they're g…

Power Hungry Cows Time Limit: 1000MS   Memory Limit: 30000K Total Submissions: 5522   Accepted: 1384 Description FJ's cows would like to be able to compute integer powers P (1 <= P <= 20,000) of numbers very quickly, but need your help. Because they…

题目地址:http://poj.org/problem?id=2109 /* 题意:k ^ n = p,求k 1. double + pow:因为double装得下p,k = pow (p, 1 / n); 基础知识: 类型 长度 (bit) 有效数字 绝对值范围 float 32 6~7 10^(-37) ~ 10^38 double 64 15~16 10^(-307) ~ 10^308 long double 128 18~19 10^(-4931) ~ 10 ^ 4932 2. 二分查找…

1669: [Usaco2006 Oct]Hungry Cows饥饿的奶牛 Time Limit: 5 Sec  Memory Limit: 64 MBSubmit: 665  Solved: 419[Submit][Status] Description Farmer John养了N(1 <= N <= 5,000)头奶牛,每头牛都有一个不超过32位二进制数的正整数编号.FJ希望奶牛们在进食前,能按编号从小到大的顺序排好队,但奶牛们从不听他的话.为了让奶牛们养成这个习惯,每次开饭时,FJ从奶…

裸的LIS ----------------------------------------------------------------- #include<cstdio> #include<cstring> #include<algorithm> #include<iostream>   #define rep( i , n ) for( int i = 0 ;  i < n ; ++i ) #define clr( x , c ) memset…

POJ 1459 Power Network / HIT 1228 Power Network / UVAlive 2760 Power Network / ZOJ 1734 Power Network / FZU 1161 (网络流,最大流) Description A power network consists of nodes (power stations, consumers and dispatchers) connected by power transport lines. A…

POJ 2387 Til the Cows Come Home (图论,最短路径) Description Bessie is out in the field and wants to get back to the barn to get as much sleep as possible before Farmer John wakes her for the morning milking. Bessie needs her beauty sleep, so she wants to g…

POJ.2387 Til the Cows Come Home (SPFA) 题意分析 首先给出T和N,T代表边的数量,N代表图中点的数量 图中边是双向边,并不清楚是否有重边,我按有重边写的. 直接跑spfa,dij,floyd都可以. 求1到N的最短路. 代码总览 #include <cstdio> #include <cstring> #include <algorithm> #include <queue> #include <stack>…