P3147 [USACO16OPEN]262144一道非常有趣的游戏,不,题目.当数据水时,可以这样表示状态.f[i][j]表示合并[i,j]区间所能得到的最大值,有点floyed的小味道.if(f[i][k]==f[k+1][j])f[i][j]=max(f[i][k]+1,f[i][j]);不断更新答案.这样需要枚举左右端点和中间点,O(n^3)300以内的数据可以水过.状态的设定直接把dp拉到暴力里去了. #include<iostream> #include<cstdio>…

P3147 [USACO16OPEN]262144 题目描述 Bessie likes downloading games to play on her cell phone, even though she doesfind the small touch screen rather cumbersome to use with her large hooves. She is particularly intrigued by the current game she is playing.…

P3147 [USACO16OPEN]262144 题目描述 Bessie likes downloading games to play on her cell phone, even though she doesfind the small touch screen rather cumbersome to use with her large hooves. She is particularly intrigued by the current game she is playing.…

注:两道题目题意是一样的,但是数据范围不同,一个为弱化版,另一个为强化版. P3146传送门(弱化版) 思路: 区间动规,设 f [ i ][ j ] 表示在区间 i ~ j 中获得的最大值,与普通区间动规最大的不同在于:只有左区间的最大值等于右区间的最大值时才能够进行转移. AC代码: #include<cstdio> #include<cstring> #include<cmath> #include<algorithm> #include<cst…

https://www.luogu.org/problemnew/show/P3147 此题与上一题完全一样,唯一不一样的就是数据范围; 上一题是248,而这一题是262144; 普通的区间dp表示状态表示法根本存不下, 这时我们就要想另外的状态表示法; #include <bits/stdc++.h> #define read read() #define up(i,l,r) for(int i = (l);i <=(r); i++) using namespace std; int…

传送门啦 其实大家可以先看一下这个题 [USACO16OPEN]248 分析: 数据范围很奇特:n特别,a[i]特别——如果O(N^3)能接受就直接区间DP水过了,但是不行,于是考虑设计一个状态囊括a[i]. 注意到a[i]每次合并只+1,于是想到答案其实就是最大的被合并的数+1,并且可以按a[i]从小到大的顺序DP. 状态:f[i][j]表示从第j个数向右合并成数字i的下标的下一位. 状态转移方程:f[i][j] = f[i-1][f[i-1][j]] #include <iostream>…

发现这个数列的范围特别大但是值域的范围特别小 于是可以大胆猜测这道题值域肯定需要开到状态里去 又发现\(262144=2^{18}\)这个暗示非常明显啊,暗示这道题跟二进制有关系 其实也没什么关系 设\(dp[i][j]\)表示从\(i\)位置开始合并,合并出\(j\)这个数所合并的区间的尾位置在哪里 之后就会发现这个转移非常像倍增 \[dp[i][j+1]=dp[dp[i][j]+1][j]\] 就这样了,暴力合并就可以了 同时值域范围需要开到\(40+log_2{262148}=58\) 代…

题目描述 Bessie likes downloading games to play on her cell phone, even though she doesfind the small touch screen rather cumbersome to use with her large hooves. She is particularly intrigued by the current game she is playing.The game starts with a seq…

感觉上这个题是可以直接暴力的,每次根据一段连续最小值个数的奇偶性决定是否划分区间,递归处理.然而写起来实在太麻烦了. 设f[i][j]为以i为左端点合并出j时的右端点.则有f[i][j]=f[f[i][j-1]+1][j-1].类似于区间dp. #include<iostream> #include<cstdio> #include<cmath> #include<cstdlib> #include<cstring> #include<al…

题目描述 给定一个1*n的地图,在里面玩2048,每次可以合并相邻两个(数值范围1-262,144),问最大能合出多少.注意合并后的数值并非加倍而是+1,例如2与2合并后的数值为3. 这道题的思路: 这是上一道题的数据强化版,数据达到了 260000. 所以只能 O(nlogn) 的时间复杂度过. 然后就发现根本就已经不是一道题目了,方程和处理方式完全不一样.    非动规版本 非动规版本是动用了一个数据结构---栈. 比较巧妙. 因为这道题有带一点贪心的思想在里面,因为所有的元素就只有那些,所…

链接: P3147 P3146双倍经验 前言: 今天发现的一道很有意思的DP题 分析: 第一眼以为是区间DP,于是设f[i][j]为从第i个数到第j个数可以合出的最大值,但思考后发现并不能简单合并,并且n的范围也不支持. 于是想贪心,但是贪着贪着发现自己想不出,于是看题解,发现唯一的贪心也被hack了,果然正解不是贪心. 决定放弃. 于是回头重新看题分析,首先根据n的范围分析后可以发现答案范围很小,最大为58,又回到刚开始的区间DP,我们发现其中有三个关键值,左端点,右端点和答案,那么我们可以尝…

P3147 [USACO16OPEN]262144 题目描述 Bessie likes downloading games to play on her cell phone, even though she doesfind the small touch screen rather cumbersome to use with her large hooves. She is particularly intrigued by the current game she is playing.…

P4095 [HEOI2013]Eden 的新背包问题   P2657 [SCOI2009]windy数   P3413 SAC#1 - 萌数   P3205 [HNOI2010]合唱队   P4767 [IOI2000]邮局   P3147[USACO16OPEN]262144   P3146 [USACO16OPEN]248   P1070 道路游戏   P1095 守望者的逃离   P1108 低价购买   P1174 打砖块   P1351 联合权值   P1578 奶牛浴场   P16…

记录一些基础的区间 \(\text{DP}\) 题. 0x00 AT_dp_n N - Slimes 最板的区间 \(\text{DP}\) . 记 \(f[i][j]\) 表示合并 \(i\sim j\) 区间的最小代价,初始化为 \(\text{inf}\),\(f[i][i]=0\) (一个数不需要代价). 第一维从小到大枚举区间长度 \(len\),第二维枚举左端点 \(i\),同时可以计算出右端点 \(j=i+len-1\),第三维枚举段点 \(k\),转移方程为 \[f[i][j]=…

Description 在1*n的序列中,每次可以合并两个相邻且相等的数,变成它们两个加1,求最大的数. Solution 设\(f[i][j]\)表示\([i,k)\)这个区间能合并出\(j\)的最小的\(k\),\(f[i][j] = f[f[i][j-1]][j-1]\). Code #include <cstdio> const int N = 262144 + 10; int n, f[N][60]; int main() { scanf("%d", &n…

Description 一个序列,每次可以将两个相同的数合成一个数,价值+1,求最后最大价值 \(n \leqslant 262144\) Sol DP. 这道题是 BZOJ 4580: [Usaco2016 Open]248 加强版. 做248的那个区间DP其实很多方案都是0,而且一个区间中只有一个合法的数字. 然后就是 一个区间合成一个数的方案的这个数字是固定的. \(f[i][j]\) 表示以 \(i\) 结尾是否能合成 \(j\),同时记录一下转移位置,每次向前找前一个指针就可以了. 复…

elasticsearch启动时遇到的错误 问题翻译过来就是:elasticsearch用户拥有的内存权限太小,至少需要262144: 解决: 切换到root用户 执行命令: sysctl -w vm.max_map_count=262144 查看结果: sysctl -a|grep vm.max_map_count 显示: vm.max_map_count = 262144 上述方法修改之后,如果重启虚拟机将失效,所以: 解决办法: 在   /etc/sysctl.conf文件最后添加一行 v…

题目大意: 给出n个数a[1..n],n<=262144,a[i]<=40,相邻且相同的数可以合并成一个并将值加1,问能获得的最大数是多少 用一个双向链表维护原数列,每个节点记录此节点对应的数值和数的个数,合并相邻且对应数值相同的节点 每次选一个数值最小的点处理,此时两侧的数都更大 若这个点只有一个数则直接删去并断开两侧,此时两侧的数不可能再互相合并 若这个点有偶数个数则数值+1,个数/2,检测能否和两侧合并 若这个点有奇数个数,两侧的数也不可能再互相合并了,因此将这个点分裂成两个互不相连的点…

P3143 [USACO16OPEN]钻石收藏家Diamond Collector 题目描述 Bessie the cow, always a fan of shiny objects, has taken up a hobby of mining diamonds in her spare time! She has collected \(N\) diamonds (\(N \leq 50,000\) of varying sizes, and she wants to arrange so…

262144 (game) 题目描述 Bessie likes downloading games to play on her cell phone, even though she does find the small touch screen rather cumbersome to use with her large hooves. She is particularly intrigued by the current game she is playing. The game s…

P3145 [USACO16OPEN]分割田地Splitting the Field 题目描述 Farmer John's NN cows (3 \leq N \leq 50,0003≤N≤50,000) are all located at distinct positions in his two-dimensional field. FJ wants to enclose all of the cows with a rectangular fence whose sides are pa…

P3146 [USACO16OPEN]248 题目描述 Bessie likes downloading games to play on her cell phone, even though she doesfind the small touch screen rather cumbersome to use with her large hooves. She is particularly intrigued by the current game she is playing.The…

题目描述 Bessie likes downloading games to play on her cell phone, even though she doesfind the small touch screen rather cumbersome to use with her large hooves. She is particularly intrigued by the current game she is playing.The game starts with a seq…

P3146 [USACO16OPEN]248 题目描述 Bessie likes downloading games to play on her cell phone, even though she doesfind the small touch screen rather cumbersome to use with her large hooves. She is particularly intrigued by the current game she is playing.The…

P3143 [USACO16OPEN]钻石收藏家Diamond Collector 题目描述 Bessie the cow, always a fan of shiny objects, has taken up a hobby of mining diamonds in her spare time! She has collected NN diamonds (N \leq 50,000N≤50,000) of varying sizes, and she wants to arrange…

P3146 [USACO16OPEN]248 题解 第一道自己码出的区间DP快庆祝一哈 2048 每次可以合并任意相邻的两个数字,得到的不是翻倍而是+1 dp[L][R] 区间 L~R 合并结果 然后拆成左区间和右区间,看看他们能不能合并,更新ans 注意如果最后枚举到的总区间 1~n ,那么就要考虑取左右区间最大值了,因为可能左右区间不能合并,那么左右区间最大值就是最终答案 代码 #include<iostream> #include<cstdio> #include<st…

[USACO16OPEN]248 G 题目描述 Bessie likes downloading games to play on her cell phone, even though she doesfind the small touch screen rather cumbersome to use with her large hooves. She is particularly intrigued by the current game she is playing.The gam…

[USACO16OPEN]248 G 题目: 题目描述 Bessie likes downloading games to play on her cell phone, even though she doesfind the small touch screen rather cumbersome to use with her large hooves. She is particularly intrigued by the current game she is playing.The…

1.由于登不上云的节点 不采用修改节点配置的方式 修改部署的stateful 加上 initContainers 它和 containers 同一层级的 initContainers: - name: sysctl securityContext: privileged: true command: ['sh', '-c', 'sysctl -w vm.max_map_count=262144'] image: xxx.xxx.com/elasticsearch:7.4.2 2.重新等一会  或…

一.描述 最近在批量上传文件时网关出现了异常,后面发现上传大文件也会出现文件超过256发生异常,异常信息如下: org.springframework.core.io.buffer.DataBufferLimitException: Exceeded limit on max bytes to buffer : 262144 at org.springframework.core.io.buffer.LimitedDataBufferList.raiseLimitException(Limite…