Language: Default Power Strings Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 33205   Accepted: 13804 Description Given two strings a and b we define a*b to be their concatenation. For example, if a = "abc" and b = "def"…

Power Strings POJ - 2406 时限: 3000MS   内存: 65536KB   64位IO格式: %I64d & %I64u 提交 状态 已开启划词翻译 问题描述 Given two strings a and b we define a*b to be their concatenation. For example, if a = "abc" and b = "def" then a*b = "abcdef".…

链接: http://poj.org/problem?id=2406 Power Strings Time Limit:3000MS     Memory Limit:65536KB     64bit IO Format:%I64d & %I64u Submit Status Description Given two strings a and b we define a*b to be their concatenation. For example, if a = "abc&qu…

 字符串前缀的阶 题目大意:求前缀的阶 和POJ1961是一样的,KMP的Next数组的应用,不要用STL,不要一个一个读入字符(IO永远是最慢的) #include <iostream> #include <algorithm> #include <functional> #include <string.h> using namespace std; ]; ]; void Input(int &); void Get_Next(const int…

Given two strings a and b we define a*b to be their concatenation. For example, if a = "abc" and b = "def" then a*b = "abcdef". If we think of concatenation as multiplication, exponentiation by a non-negative integer is defin…

题目大意:叙述的比较高大上,其实就是一个字符串B = AAAAAAA,求出来这个A最短有多长   分析:注意如果这个串不是完全循环的,那么循环节就是就是它本身.   代码如下: #include<stdio.h> #include<string.h> ; ; char s[MAXN]; int next[MAXN]; void GetNext(int N) { , j=-; next[] = -; while(i < N) { || s[i]==s[j]) next[++i]…

后缀数组专题的 emm.. 就next 循环节../ 有后缀数组也可以做 从小到大枚举长度i,如果长度i的子串刚好是重复了len/i次,应该满足len % i == 0和rank[0] - rank[i] == 1(整个串的等级比 i位置开始的后缀的等级大1  (i位置开始的后缀即为比总串低一个等级的后缀)) 和height[rank[0]] == len-i (整个串 和 比它低一个等级的串的最长公共前缀的长度 是总长度减去这个循环节的长度)这些条件的 #include <iostream>…

Power Strings Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 28859   Accepted: 12045 Description Given two strings a and b we define a*b to be their concatenation. For example, if a = "abc" and b = "def" then a*b = "…

Description Given two strings a and b we define a*b to be their concatenation. For example, if a = "abc" and b = "def" then a*b = "abcdef". If we think of concatenation as multiplication, exponentiation by a non-negative inte…

首先先讲一下KMP算法作用: KMP就是来求在给出的一串字符(我们把它放在str字符数组里面)中求另外一个比str数组短的字符数组(我们叫它为ptr)在str中的出现位置或者是次数 这个出现的次数是可以重叠的 例如:在数组   ababa    中  aba的出现次数-----------它的答案是2------分别是从[0---2]  [2---4] 他们是可以重叠的,但是不可以完全重叠(废话T_T) KMP算法主要有两个模板 1.https://blog.csdn.net/starstar1…