Leetcode_131. Palindrome Partitioning_[DFS]】的更多相关文章

题目链接 Given a string s, partition s such that every substring of the partition is a palindrome. Return all possible palindrome partitioning of s. Example: Input: "aab" Output: [ ["aa","b"], ["a","a","b…
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Palindrome Partitioning Total Accepted: 21056 Total Submissions: 81036My Submissions Given a string s, partition s such that every substring of the partition is a palindrome. Return all possible palindrome partitioning of s. For example, given s = "a…
题目传送门 题意:给出一个字符串,将字符串中所有的回文子串全部放入一个集合里,去重后.问这个集合里有几对<a,b>,使得a是b的子串. 思路:一开始想偏了,以为只要求每个回文串的回文后缀的数量加去掉开头结尾字符的数量就可以了.事实上,如果我们把去掉两个字符的字符串称为父节点,那么父节点的回文后缀和自己也能形成这样的pair. 设一个字符串x能产生的贡献为$dp[x]$,我们考虑x能产生的贡献是什么呢? 一个是和自己本身的所有回文后缀结合产生的贡献,这一个可以通过回文树上跳fail来完成. 一个…
题目传送门 题意 给一个字符串s,然后将s中所有本质不同回文子串放到一个集合S里面,问S中的两个元素\(a,b\)满足\(a\)是\(b\)的子串的个数. 分析 首先要会回文树(回文自动机,一种有限状态自动机) 然后可以很轻松的求出来S集合,我们拿出一个样例画出回文树看一下 abacaba 注: 上图中结点序号只是为了方便描述,与实际建树并不一定相同 0和1分别为偶数根和奇数根,黄边为fail边,总共有7个本质不同的回文串. 在计算答案时,我们从上到下统计,例如计算aba作为母串时的答案,那么子…
Given a string s, partition s such that every substring of the partition is a palindrome. Return all possible palindrome partitioning of s. For example, given s = "aab",Return [ ["aa","b"], ["a","a","…
参考:http://www.cppblog.com/wicbnu/archive/2013/03/18/198565.html 我太喜欢用dfs和回溯法了,但是这些暴力的方法加上剪枝之后复杂度依然是很高,显然不能达到题目的要求. 这个时候应该考虑动态规划,并且要复杂度尽量接近O(n^2)的算法. 下面这个方法更加简洁:自长到短找到回文串后,往后dfs,并记录递归深度表示并更新最小划分数.http://fisherlei.blogspot.com/2013/03/leetcode-palindro…
Given a string s, partition s such that every substring of the partition is a palindrome. Return all possible palindrome partitioning of s. For example, given s = "aab",Return [ ["aa","b"], ["a","a","…
Given a string s, partition s such that every substring of the partition is a palindrome. Return all possible palindrome partitioning of s. For example, given s = "aab",Return [ ["aa","b"], ["a","a","…
原题链接在这里:https://leetcode.com/problems/palindrome-permutation-ii/ 题目: Given a string s, return all the palindromic permutations (without duplicates) of it. Return an empty list if no palindromic permutation could be form. For example: Given s = "aabb&…
D. Tree Requests time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Roman planted a tree consisting of n vertices. Each vertex contains a lowercase English letter. Vertex 1 is the root of the…
Palindrome Partitioning Given a string s, partition s such that every substring of the partition is a palindrome. Return all possible palindrome partitioning of s. For example, given s = "aab", Return [ ["aa","b"], ["a&q…
Given a string s, partition s such that every substring of the partition is a palindrome. Return all possible palindrome partitioning of s. For example, given s = "aab", Return [ ["aa","b"], ["a","a","…
题目: Given a string s, partition s such that every substring of the partition is a palindrome. Return all possible palindrome partitioning of s. For example, given s = "aab", Return [ ["aa","b"], ["a","a",&…
LeetCode:Palindrome Partitioning 题目如下:(把一个字符串划分成几个回文子串,枚举所有可能的划分) Given a string s, partition s such that every substring of the partition is a palindrome. Return all possible palindrome partitioning of s. For example, given s = "aab",Return [ […
题目: Given a string s, partition s such that every substring of the partition is a palindrome. Return the minimum cuts needed for a palindrome partitioning of s. For example, given s = "aab", Return 1 since the palindrome partitioning ["aa&q…
Make Palindrome Time Limit:3000MS     Memory Limit:0KB     64bit IO Format:%lld & %llu Submit Status Practice UVA 10453 #include <stdio.h> #include <string.h> #include <algorithm> using namespace std; ]; ][],react[][]; int dfs(int x,…
335B - Palindrome 题目: 给出一个字符串(均有小写字母组成),如果有长度为100的回文子串,输出该子串.否则输出最长的回文子串. 分析: 虽然输入串的长度比较长,但是如果存在单个字母100或以上的话,直接输出即可. 利用抽屉原理发现,如果不存在上面所说的情况,长度不会超过26*99 dp[l][r]表示l到r的回文子串的长度,dp转移方式比较明显,记录一下得到最优值时的位置. 输出方案时,如果dp[1][len]>=100的话,显然可以输出长度100的子串,否则直接输出该长度.…
Palindrome Partitioning Given a string s, partition s such that every substring of the partition is a palindrome. Return all possible palindrome partitioning of s. For example, given s = "aab",Return [ ["aa","b"], ["a&qu…
https://leetcode.com/problems/palindrome-partitioning/ Given a string s, partition s such that every substring of the partition is a palindrome. Return all possible palindrome partitioning of s. For example, given s = "aab",Return [ ["aa&qu…
Palindrome Permutation I Given a string, determine if a permutation of the string could form a palindrome. For example,"code" -> False, "aab" -> True, "carerac" -> True. Hint: Consider the palindromes of odd vs even…
Given a string s, partition s such that every substring of the partition is a palindrome. Return all possible palindrome partitioning of s. For example, given s = "aab",Return [ ["aa","b"], ["a","a","…
Question Given a string s, return all the palindromic permutations (without duplicates) of it. Return an empty list if no palindromic permutation could be form. For example: Given s = "aabb", return ["abba", "baab"]. Given s…
Palindrome Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 58277   Accepted: 20221 Description A palindrome is a symmetrical string, that is, a string read identically from left to right as well as from right to left. You are to write a…
最短路径=>BFS    所有路径=>DFS 126. Word Ladder II BFS+DFS: BFS找出下一个有效的word进队 并记录step 更新两个变量:unordered_map<string, vector<string>> next, unordered_map<string,int> visit DFS找出所有的解法 更新两个变量:vector<vector<string>> result, vector<…
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1513 题意: 给你一个字符串s,你可以在s中的任意位置添加任意字符,问你将s变成一个回文串最少需要添加字符的个数. 题解1(LCS): 很神奇的做法. 先求s和s的反串的LCS,也就是原串中已经满足回文性质的字符个数. 然后要变成回文串的话,只需要为剩下的每个落单的字符,相应地插入一个和它相同的字符即可. 所以答案是:s.size()-LCS(s,rev(s)) 另外,求LCS时只会用到lcs[i-…
H. Special Palindrome time limit per test:1 second memory limit per test:64 megabytes input:standard input output:standard output A sequence of positive and non-zero integers called palindromic if it can be read the same forward and backward, for exa…
1 Palindrome Partitioning 问题来源:Palindrome Partitioning 该问题简单来说就是给定一个字符串,将字符串分成多个部分,满足每一部分都是回文串,请输出所有可能的情况. 该问题的难度比较大,很可能第一次遇到没有思路,这很正常.下面我们一点点分析,逐步理清思路.先不考虑所有的情况,针对一个符合条件的划分,每一部分都是一个回文子串,而且各部分的长度不固定.也即每一部分都是原始字符串的一个子串,且满足回文条件.所有的划分都满足上述条件,所以这就启发我们首先判…
Given a string s, partition s such that every substring of the partition is a palindrome. Return all possible palindrome partitioning of s. Example: Input: "aab" Output: [ ["aa","b"], ["a","a","b"…
131. Palindrome Partitioning substr使用的是坐标值,不使用.begin()..end()这种迭代器 使用dfs,类似于subsets的题,每次判断要不要加入这个数 start每次是起始的位置,判断当前位置到起始位置是不是回文 class Solution { public: vector<vector<string>> partition(string s) { vector<vector<string> > result;…