题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=4003 Humans have discovered a kind of new metal mineral on Mars which are distributed in point‐like with paths connecting each of them which formed a tree. Now Humans launches k robots on Mars to collect…
Find Metal Mineral Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65768/65768 K (Java/Others) Total Submission(s): 2018 Accepted Submission(s): 913 Problem Description Humans have discovered a kind of new metal mineral on Mars which are d…
HDU 5862 Counting Intersections(离散化+树状数组) 题目链接http://acm.split.hdu.edu.cn/showproblem.php?pid=5862 Description Given some segments which are paralleled to the coordinate axis. You need to count the number of their intersection. The input data guarant…
Triple Time Limit: 12000/6000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 388 Accepted Submission(s): 148 Problem Description Given the finite multi-set A of n pairs of integers, an another finite multi-set B …
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1394 Minimum Inversion Number Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 10…
Counting Intersections 题目链接: http://acm.split.hdu.edu.cn/showproblem.php?pid=5862 Description Given some segments which are paralleled to the coordinate axis. You need to count the number of their intersection. The input data guarantee that no two se…
ZYB's Game Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=5592 Description ZYB has a premutation P,but he only remeber the reverse log of each prefix of the premutation,now he ask you to restore the premutation…
Sort it Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 4672 Accepted Submission(s): 3244 Problem Description You want to processe a sequence of n distinct integers by swapping two adjacent s…
题目链接 Problem Description Given the finite multi-set A of n pairs of integers, an another finite multi-set B of m triples of integers, we define the product of A and B as a multi-set C=A∗B={⟨a,c,d⟩∣⟨a,b⟩∈A, ⟨c,d,e⟩∈B and b=e} For each ⟨a,b,c⟩∈C, its B…
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=6447 Problem DescriptionYJJ is a salesman who has traveled through western country. YJJ is always on journey. Either is he at the destination, or on the way to destination.One day, he is going to travel…
题目链接:[http://acm.split.hdu.edu.cn/showproblem.php?pid=5517] 题意:定义multi_set A<a , d>,B<c , d , e>,C<x , y , z>,给出 A , B ,定义 C = A * B = ={⟨a,c,d⟩∣⟨a,b⟩∈A, ⟨c,d,e⟩∈B and b=e} .求出C之后,求C中一个元素t[i]<a , b , c>是否存在一个元素tmp<x , y , z>使…
题目链接: http://acm.split.hdu.edu.cn/showproblem.php?pid=5862 Counting Intersections Time Limit: 12000/6000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others) 问题描述 Given some segments which are paralleled to the coordinate axis. You need to coun…
题意: 一棵有权树,从根结点中放入 K 个机器人.求用这 K 个机器人遍历全部的结点最少的权值和. 思路: 1. dp[u][i] 表示给以 u 为根节点的子树放 i 个机器人,遍历其子树所须要的最小权值. 2. 关键在于 dp[u][0] 的理解,表示:最后停留在以 u 为根节点的子树下 0 个机器人,而且遍历了 u 子树的最小权值和. 3. 以下的步骤就变成和分组背包类似的情况了,根节点 u 给孩子 v 放多少个机器人. 4. dp[u][i] = min(dp[u][i], dp[u][j…
GCD Array Time Limit: 11000/5500 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 843 Accepted Submission(s): 205 Problem Description Teacher Mai finds that many problems about arithmetic function can be reduced to…
