Power Strings[poj2406]题解】的更多相关文章

Power Strings Description - Given two strings a and b we define ab to be their concatenation. For example, if a = "abc" and b = "def" then ab = "abcdef". If we think of concatenation as multiplication, exponentiation by a non…
Power Strings Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 29402   Accepted: 12296 Description Given two strings a and b we define a*b to be their concatenation. For example, if a = "abc" and b = "def" then a*b = "…
相比一般KMP,构建next数组需要多循环一次,因为next[j]代表前j-1个字符的最长相同前缀后缀,比如字符串为aab aab aab共9个字符,则next[10]等于前9个字符中最长相同前缀后缀长度,如果字符串是由某个子串比如aab循环而形成的,则next[10]就会等于(字符串长度len-循环子串长度).但是需要注意aab aab aa这种情况,算出来结果是不能被len整除的,需要特判 #include <iostream> #include <cstdio> #inclu…
Power Strings Description Given two strings a and b we define a*b to be their concatenation. For example, if a = "abc" and b = "def" then a*b = "abcdef". If we think of concatenation as multiplication, exponentiation by a non…
poj2406 Power Strings(kmp) 给出一个字符串,问这个字符串是一个字符串重复几次.要求最大化重复次数. 若当前字符串为S,用kmp匹配'\0'+S和S即可. #include <cstdio> #include <cstring> using namespace std; const int maxn=2e6+5; char s1[maxn], s2[maxn]; int n1, n2, nxt[maxn], ans; int main(){ while (~…
题目链接:https://vjudge.net/problem/POJ-2406 Power Strings Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 52631   Accepted: 21921 Description Given two strings a and b we define a*b to be their concatenation. For example, if a = "abc"…
Power Strings   Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 47748   Accepted: 19902 Description Given two strings a and b we define a*b to be their concatenation. For example, if a = "abc" and b = "def" then a*b = &quo…
Power Strings Time Limit: 3000MS Memory Limit: 65536K Total Submissions: 39291 Accepted: 16315 Description Given two strings a and b we define a*b to be their concatenation. For example, if a = "abc" and b = "def" then a*b = "abcd…
Power Strings Time Limit : 6000/3000ms (Java/Other)   Memory Limit : 131072/65536K (Java/Other) Total Submission(s) : 29   Accepted Submission(s) : 14 Problem Description Given two strings a and b we define a*b to be their concatenation. For example,…
题目描述 PDF 输入输出格式 输入格式: 输出格式: 输入输出样例 输入样例#1: 复制 abcd aaaa ababab . 输出样例#1: 复制 1 4 3 题解 Luogu的题解 这里是对目前最高赞题解结论的证明. 结论:设字符串长度为$n$,最长相同前后缀的长度为$next[i]$, 如$n$%$(n-next[n])=0$,则答案为$n/(n-next[n])$,否则为$1$. 证明: 我们求$next$数组的时候,相当于每次把当前串这样对齐了一下↓ 而$next$求到$n$时,上面…