Given an input string, reverse the string word by word. For example, Given s = "the sky is blue", return "blue is sky the". 解题思路: 本题方法多多,最简单的方式直接按“ ” spilt即可,JAVA实现如下: public String reverseWords(String s) { if (s == null || s.length()…

Given an input string, reverse the string word by word. For example,Given s = "the sky is blue",return "blue is sky the". Update (2015-02-12):For C programmers: Try to solve it in-place in O(1) space. Clarification: What constitutes a…

Given an input string, reverse the string word by word. For example,Given s = "the sky is blue",return "blue is sky the". Update (2015-02-12):For C programmers: Try to solve it in-place in O(1) space. 倒序字符串. 注意使用BufferString,因为如果使用Stri…

Given an input string, reverse the string word by word. Example: Input: "the sky is blue",Output: "blue is sky the".Note: A word is defined as a sequence of non-space characters.Input string may contain leading or trailing spaces. Howe…

Given an input string, reverse the string word by word. For example, Given s = "the sky is blue", return "blue is sky the". Update (2015-02-12): For C programmers: Try to solve it in-place in O(1) space. 这题遇到的困难主要是细节地方处理的不好:(1)空格的处理,(2…

原题地址 将单词按空格分词,然后倒序拼接即可 代码: void reverseWords(string &s) { vector<string> words; ; ; ; i < s.length(); i++) { if (s[i] == ' ') { ) words.push_back(s.substr(start, len)); len = ; } else { ) { start = i; len = ; } else len++; } } ) words.push_ba…

Given an input string, reverse the string word by word. A word is defined as a sequence of non-space characters.The input string does not contain leading or trailing spaces and the words are always separated by a single space.For example,Given s = "t…

Given a string, you need to reverse the order of characters in each word within a sentence while still preserving whitespace and initial word order. Example 1: Input: "Let's take LeetCode contest" Output: "s'teL ekat edoCteeL tsetnoc"…

Reverse a linked list from position m to n. Do it in-place and in one-pass. For example: Given 1->2->3->4->5->NULL, m = 2 and n = 4, return 1->4->3->2->5->NULL. Note: Given m, n satisfy the following condition: 1 ≤ m ≤ n ≤ le…

557. Reverse Words in a String III 最简单的把空白之间的词反转 class Solution { public: string reverseWords(string s) { vector<int> blank; ;i < s.size();i++){ if(s[i] == ' ') blank.push_back(i); } ; int end; ;i < blank.size();i++){ end = blank[i] - ; revers…