考虑离线操作,求出每个向量存在的时间区间,用时间线段树来进行分治,在每个节点求出凸壳后,询问时在凸壳上三分答案.时间复杂度$O(n\log^2n)$. #include<cstdio> #include<algorithm> typedef long long ll; const int N=200010,M=4000000; int n,m,i,op,x,y,g[524300],v[M],nxt[M],ed,t;ll ans[N]; inline void read(int&am…
Implement an iterator to flatten a 2d vector. For example,Given 2d vector = [ [1,2], [3], [4,5,6] ] By calling next repeatedly until hasNext returns false, the order of elements returned by next should be: [1,2,3,4,5,6]. Hint: How many variables do y…
quiver3,空间向量场图 [x, y] = meshgrid(-2:0.2:2, -1:0.1:1); z = x.*exp(-x.^2-y.^2); [u, v, w] = surfnorm(x, y, z); %找出与曲面上各个点垂直的向量(u, v, w),注意已经归一化 quiver3(x, y, z, u, v, w); hold on, surf(x, y, z); hold off axis equal %colormap('default') 参考:http://anon…