题意:求两数最大公约数和最小公倍数. 类型:辗转相除法 算法:gcd(a,b)=gcd(b,a%b),lcm(a,b)=a*b/gcd(a,b). #include <cstdio> #include <iostream> using namespace std; int gcd(int a, int b) { for(int t; t = a % b; a = b, b = t); return b; } int main() { int a, b, g; long long l…
GCD and LCM Descriptions: Write a program which computes the greatest common divisor (GCD) and the least common multiple (LCM) of given a and b. Input Input consists of several data sets. Each data set contains a and b separated by a single space in…
组合数学 GCD and LCM Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65535/65535 K (Java/Others)Total Submission(s): 451 Accepted Submission(s): 216 Problem Description Given two positive integers G and L, could you tell me how many solutions…
GCD and LCM Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=4497 Description Given two positive integers G and L, could you tell me how many solutions of (x, y, z) there are, satisfying that gcd(x, y, z) = G and…
题目链接: https://cn.vjudge.net/problem/23709/origin 本题其实有坑 数据大小太大, 2的32次方,故而一定是取巧的算法,暴力不可能过的 思路是最大公因数的倍数是最小公倍数,又有a <= b所以可以知道 a = gcd, b = lcm AC代码如下: #include <cstdio> #define ll long long using namespace std; int main() { int T; scanf("%d&quo…
并不重要的前言 最近学习了一些数论知识,但是自己都不懂自己到底学了些什么qwq,在这里把知识一并总结起来. 也不是很难的gcd和lcm 显而易见的结论: 为什么呢? 根据唯一分解定理: a和b都可被分解为素因子的乘积,形如: 则显而易见的有一下结论: 相乘,得: 得证 几种求gcd的算法 欧几里得算法(辗转相除法) 辗转相减法(优化:stein_gcd) 欧几里得算法 基于事实: 实现: int gcd(int a, int b){ ) ? a : gcd( b , a % b) ; } 简短而…
GCD & LCM Inverse Time Limit: 2000MS Memory Limit: 65536K Total Submissions: 9928 Accepted: 1843 Description Given two positive integers a and b, we can easily calculate the greatest common divisor (GCD) and the least common multiple (LCM) of a a…
GCD and LCM Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65535/65535 K (Java/Others)Total Submission(s): 40 Accepted Submission(s): 22 Problem Description Given two positive integers G and L, could you tell me how many solutions of (x,…
GCD and LCM Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65535/65535 K (Java/Others) Total Submission(s): 78 Accepted Submission(s): 43 Problem Description Given two positive integers G and L, could you tell me how many solutions of (x, y, z)…
GCD and LCM Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65535/65535 K (Java/Others)Total Submission(s): 2982 Accepted Submission(s): 1305 Problem Description Given two positive integers G and L, could you tell me how many solutions of…
