自己想了一个方法判断点是不是在凸包内,先求出凸包面积,在求由点与凸包上每两个点之间的面积(点已经排好序了),如果两者相等,则点在凸包内,否则不在(时间复杂度可能有点高)但是这题能过 #include<map> #include<set> #include<cmath> #include<queue> #include<stack> #include<vector> #include<cstdio> #include<…

Cows Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 6199   Accepted: 2822 Description Your friend to the south is interested in building fences and turning plowshares into swords. In order to help with his overseas adventure, they are f…

Cows Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 7038   Accepted: 3242 Description Your friend to the south is interested in building fences and turning plowshares into swords. In order to help with his overseas adventure, they are f…

点此看题面 大致题意: 告诉你若干个矩形的重心坐标.长.宽和相对\(y\)轴的偏转角度,求矩形面积和与能围住这些矩形的最小凸包面积之比. 矩形面积和 这应该是比较好求的吧. 已经给了你长和宽,直接乘起来累加即可. 最小凸包面积 这道题关键还是在于求凸包面积. 首先,我们要注意将题目中给出的角度转换成弧度,还要记得取相反数,不然调死你. 这段代码可以与旋转函数放在一起: inline Point Rotate(Vector A,double deg) { register double rad=d…

面向对象编程示例:求周长和面积 #define _CRT_SECURE_NO_WARNINGS #include <iostream> using namespace std; //圆的周长 double getCircleGirth(double r) { return 2 * 3.14*r; } //源的面积 double getCircleArea(double r) { return 3.14*r*r; } //用面向对象实现 //圆类 class Circle { public: v…

题目链接:https://vjudge.net/problem/POJ-3348 题意:转换题意后即是求凸包的面积. 思路: 套模板,求凸包面积即转换为多个三角形面积之和,用叉积求,然后除2,因为本题除50,所以最后除100. AC code: #include<cstdio> #include<cstring> #include<algorithm> #include<cmath> using namespace std; ; const double P…

    题目链接:    http://acm.swust.edu.cn/problem/0249/   麦兜是个淘气的孩子.一天,他在玩钢笔的时候把墨水洒在了白色的墙上.再过一会,麦兜妈就要回来了,麦兜为了不让妈妈知道这件事情,就想用一个白色的凸多边形把墙上的墨点盖住.你能告诉麦兜最小需要面积多大的凸多边形才能把这些墨点盖住吗? 现在,给出了这些墨点的坐标,请帮助麦兜计算出覆盖这些墨点的最小凸多边形的面积. Description 多组测试数据.第一行是一个整数T,表明一共有T组测试数据. 每…

Cows Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 8122   Accepted: 3674 Description Your friend to the south is interested in building fences and turning plowshares into swords. In order to help with his overseas adventure, they are f…

Description Being the only living descendant of his grandfather, Kamran the Believer inherited all of the grandpa's belongings. The most valuable one was a piece of convex polygon shaped farm in the grandpa's birth village. The farm was originally se…

package zhongqiuzuoye; //自己写的方法 public class Rect { public double width; public double height; Rect(double width,double height) //带有两个参数的构造方法,用于将width和height属性初化; { this.width=width; this.height=height; } Rect() //不带参数的构造方法,将矩形初始化为宽和高都为10. { width=10…