https://vjudge.net/problem/UVA-10870 裸的矩阵快速幂 注意系数矩阵在前面 因为系数矩阵为d*d 方程矩阵为d * 1 放反了就是d * 1 d * d 不符合矩阵乘法 #include<bits/stdc++.h> using namespace std; typedef long long ll; ; struct mat { ll a[N][N]; } x, g; int n, m, d; ll a[N], f[N]; mat operator * (m…
Consider recurrent functions of the following form:f(n) = a1f(n - 1) + a2f(n - 2) + a3f(n - 3) + : : : + adf(n - d); for n > d;where a1, a2, -, ad are arbitrary constants.A famous example is the Fibonacci sequence, defned as: f(1) = 1, f(2) = 1, f(n)…
Again Prime? No time.Input: standard inputOutput: standard outputTime Limit: 1 second The problem statement is very easy. Given a number n you have to determine the largest power of m, not necessarily prime, that divides n!. Input The input file cons…