链接 dp好想  根据它定义的 记忆化下就行 路径再dfs一遍 刚开始以为要判空格 所以加了判空格的代码 后来知道不用 .. #include <iostream> #include<cstdio> #include<cstring> #include<algorithm> #include<stdlib.h> using namespace std; #define INF 0xffffff ][]; ],q[]; int dfs(int a,…

题目传送门 /* 题意:就是从上到下,找到最短路,输出路径 DP+路径:状态转移方程:dp[i][j] = min (dp[i-1][j], dp[i][j-1], dp[i][j+1]) + a[[i][j]; (类似数塔问题) 关键在记录路径,可以用pre[x][y] = -1/0/1/2 区分,DFS回溯输出 详细解释:http://www.cnblogs.com/staginner/archive/2012/05/02/2479658.html */ #include <cstdio>…

In Frobnia, a far-away country, the verdicts in court trials are determined by a jury consisting of members of the general public. Every time a trial is set to begin, a jury has to be selected, which is done as follows. First, several people are draw…

题:https://codeforces.com/contest/1256/problem/E 题意:给一些值,代表队员的能力值,每组要分3个或3个以上的人,然后有个评价值x=(队里最大值-最小值),问最小的∑x是多少,以及输出方案 学习粗:https://www.cnblogs.com/Lubixiaosi-Zhaocao/p/11797744.html dp路径转移 #include<bits/stdc++.h> using namespace std; ; struct node{ in…

题目链接 很早 很早之前就看过的一题,今天终于A了.状态转移,还算好想,输出路径有些麻烦,搞了一个标记数组的,感觉不大对,一直wa,看到别人有写直接输出的..二了,直接输出就过了.. #include <cstdio> #include <cstring> #include <iostream> using namespace std; ][]; ]; ]; ]; int dfs(int L,int R) { int i,minz; if(dp[L][R]) retur…

DP + 单调队列优化 + 平衡树 好题 Description Given an integer sequence { an } of length N, you are to cut the sequence into several parts every one of which is a consecutive subsequence of the original sequence. Every part must satisfy that the sum of the intege…

//Accepted 208K 0MS //dp //最长公共子序列+路径 #include <cstdio> #include <cstring> #include <iostream> using namespace std; ; ; int dp[imax_n][imax_n]; char s1[imax_n],s2[imax_n]; int l1,l2; int max(int a,int b) { return a>b?a:b; } void Dp()…

E. LIS of Sequence Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/486/problem/E Description The next "Data Structures and Algorithms" lesson will be about Longest Increasing Subsequence (LIS for short) of a sequence.…

链接 路径麻烦啊 很多细节 倒回去搜一遍 卡了一节数据库.. #include <iostream> #include<cstdio> #include<cstring> #include<algorithm> #include<stdlib.h> using namespace std; #define LL long long ],flag; LL sum[][],dp[][],f[][]; int m,n; void dfs(int u,i…

题目:[IOI1999]花店橱窗布置 问题编号:496 题目描述 某花店现有F束花,每一束花的品种都不一样,同时至少有同样数量的花瓶,被按顺序摆成一行,花瓶的位置是固定的,从左到右按1到V顺序编号,V是花瓶的数目.花束可以移动,并且每束花用1到F的整数标识.如果I < J,则花束I必须放在花束J左边的花瓶中.例如,假设杜鹃花的标识数为1,秋海棠的标识数为2,康乃馨的标识数为3,所有花束在放入花瓶时必须保持其标识数的顺序,即杜鹃花必须放在秋海棠左边的花瓶中,秋海棠必须放在康乃馨左边的花瓶中.如果花…