最大乘积(Maximum Product,UVA 11059)】的更多相关文章

最大乘积 Maximum Product 题目链接:http://acm.hust.edu.cn/vjudge/contest/view.action?cid=84562#problem/B 解题思路: 题目意思是输入n个元素组成的序列S,找出一个乘积最大的连续子序列.若这个数不是正数,则输出0(表示无解).分析 ,连续子序列有两个要素:起点和终点,因此只需要枚举起点和终点即可.分析最大可能的乘积不会超过10的18次方,所以用 long long 来存储即可. 程序代码: #include <c…
Problem D - Maximum Product Time Limit: 1 second Given a sequence of integers S = {S1, S2, ..., Sn}, you should determine what is the value of the maximum positive product involving consecutive terms ofS. If you cannot find a positive sequence, you s…
Given a sequence of integers S = {S1, S2, . . . , Sn}, you should determine what is the value of themaximum positive product involving consecutive terms of S. If you cannot find a positive sequence,you should consider 0 as the value of the maximum pr…
Given an integer array, find three numbers whose product is maximum and output the maximum product. Example 1: Input: [1,2,3] Output: 6  Example 2: Input: [1,2,3,4] Output: 24  Note: The length of the given array will be in range [3,104] and all elem…
Given a string array words, find the maximum value of length(word[i]) * length(word[j]) where the two words do not share common letters. You may assume that each word will contain only lower case letters. If no such two words exist, return 0. Example…
作者: 负雪明烛 id: fuxuemingzhu 个人博客:http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 暴力 找最大次大 日期 题目地址:https://leetcode-cn.com/problems/maximum-product-of-two-elements-in-an-array/ 题目描述 给你一个整数数组 nums,请你选择数组的两个不同下标 i 和 j,使 (nums[i]-1)*(nums[j]-1) 取得最大值. 请你计算并返回该式的…
题目链接:https://vjudge.net/contest/210334#problem/B 题目大意:Given a sequence of integers S = {S1, S2, . . . , Sn}, you should determine what is the value of the maximum positive product involving consecutive terms of S. If you cannot find a positive sequen…
[题意]:乘积最大的子序列.n∈[1,10],s∈[-10,10] [代码]: #include<bits/stdc++.h> using namespace std; int a[105]; #define LL long long int main() { int n,f=0; LL s,ma; while(~scanf("%d",&n)) { f++; ma=0; for(int i=0;i<n;i++) scanf("%d",&am…
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注意long long  long long  longlong !!!!!!   还有 printf的时候 明明longlong型的答案 用了%d  WA了也看不出,这个细节要注意!!! #include <cstdio> ]; int main() { ;long long ans,sum; while(~scanf("%d",&n)) { ;i<n;i++) scanf("%d",&a[i]); ans=; ;i<n;i…