LeetCode(99) Recover Binary Search Tree】的更多相关文章

题目 Two elements of a binary search tree (BST) are swapped by mistake. Recover the tree without changing its structure. Note: A solution using O(n) space is pretty straight forward. Could you devise a constant space solution? 分析 给定一颗二叉排序树,它的两个节点被交换,要求…
题目 Given a binary tree, determine if it is a valid binary search tree (BST). Assume a BST is defined as follows: The left subtree of a node contains only nodes with keys less than the node's key. The right subtree of a node contains only nodes with k…
Two elements of a binary search tree (BST) are swapped by mistake. Recover the tree without changing its structure. 题意: 一颗二叉搜索树中有2个结点的元素被误换了,要求恢复二叉搜索树的原状. 思路: 中序遍历BST,若发现一次逆序,说明是两个相连结点的误换,直接交换结点的值:若发现两次逆序,则为不相连的两个结点误换,交换错误的结点即可.用一个变量保存先前结点的状态,若发生逆序则记…
题目 Given n, how many structurally unique BST's (binary search trees) that store values 1-n? For example, Given n = 3, there are a total of 5 unique BST's. 分析 此题与上题本质相同,LeetCode 95 Unique Binary Search Trees要求得到全部二叉查找树,打印其层序遍历序列. 而此题,只要求元素 [1,n] 能构成的二…
题目 Given n, generate all structurally unique BST's (binary search trees) that store values 1-n. For example, Given n = 3, your program should return all 5 unique BST's shown below. confused what "{1,#,2,3}" means? > read more on how binary tr…
题目如下: Python代码: def numTrees(self, n): """ :type n: int :rtype: int """ num=[0]*(n+1) num[0]=num[1]=1 for i in range(2,n+1): for j in range(i): num[i] += num[j]*num[i-j-1] return num[n]…
[LeetCode]99. Recover Binary Search Tree 解题报告(Python) 标签(空格分隔): LeetCode 题目地址:https://leetcode.com/problems/recover-binary-search-tree/description/ 题目描述: Two elements of a binary search tree (BST) are swapped by mistake. Recover the tree without chan…
题目链接:Recover Binary Search Tree | LeetCode OJ Two elements of a binary search tree (BST) are swapped by mistake. Recover the tree without changing its structure. Note: A solution using O(n) space is pretty straight forward. Could you devise a constan…
Recover Binary Search Tree leetcode java https://leetcode.com/problems/recover-binary-search-tree/discuss/32535/No-Fancy-Algorithm-just-Simple-and-Powerful-In-Order-Traversal 描述 解析 解决方法是利用中序遍历找顺序不对的两个点,最后swap一下就好. 因为这中间的错误是两个点进行了交换,所以就是大的跑前面来了,小的跑后面去…
Recover Binary Search Tree Two elements of a binary search tree (BST) are swapped by mistake. Recover the tree without changing its structure. Note:A solution using O(n) space is pretty straight forward. Could you devise a constant space solution? 基本…