[POJ1338]Ugly Numbers 试题描述 Ugly numbers are numbers whose only prime factors are 2, 3 or 5. The sequence 1, 2, 3, 4, 5, 6, 8, 9, 10, 12, ... shows the first 10 ugly numbers. By convention, 1 is included. Given the integer n,write a program to find an…

Ugly Numbers Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 21918 Accepted: 9788 Description Ugly numbers are numbers whose only prime factors are 2, 3 or 5. The sequence 1, 2, 3, 4, 5, 6, 8, 9, 10, 12, - shows the first 10 ugly numbers.…

转载请注明出处:viewmode=contents">http://blog.csdn.net/u012860063? viewmode=contents 题目链接:id=1338">http://poj.org/problem?id=1338 Description Ugly numbers are numbers whose only prime factors are 2, 3 or 5. The sequence  1, 2, 3, 4, 5, 6, 8, 9, 1…

https://leetcode.com/problems/ugly-number/ Write a program to check whether a given number is an ugly number. Ugly numbers are positive numbers whose prime factors only include 2, 3, 5. For example, 6, 8 are ugly while 14 is not ugly since it include…

Ugly numbers are numbers whose only prime factors are 2, 3 or 5. The sequence1, 2, 3, 4, 5, 6, 8, 9, 10, 12, 15, …shows the first 11 ugly numbers. By convention, 1 is included.Write a program to find and print the 150′th ugly number. METHOD 1 (Simple…

 Ugly Numbers  Ugly numbers are numbers whose only prime factors are 2, 3 or 5. The sequence 1, 2, 3, 4, 5, 6, 8, 9, 10, 12, 15, ... shows the first 11 ugly numbers. By convention, 1 is included. Write a program to find and print the 1500'th ugly num…

题目链接:http://poj.org/problem?id=1338 Ugly Numbers Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 21920   Accepted: 9789 Description Ugly numbers are numbers whose only prime factors are 2, 3 or 5. The sequence 1, 2, 3, 4, 5, 6, 8, 9, 10,…

丑数(Ugly Numbers, UVa 136) 题目描述 我们把只包含因子2.3和5的数称作丑数(Ugly Number).求按从小到大的顺序的第1500个丑数.例如6.8都是丑数,但14不是,因为它包含因子7.习惯上我们把1当做第一个丑数. 算法实现 版本1:错误版本 //#define LOCAL #include<iostream> #include<cstdio> #include<queue> /* 输出第1500个丑数 */ using namespac…

UVA.136 Ugly Numbers (优先队列) 题意分析 如果一个数字是2,3,5的倍数,那么他就叫做丑数,规定1也是丑数,现在求解第1500个丑数是多少. 既然某数字2,3,5倍均是丑数,且1为丑数,那么不妨从1开始算起.算完之后2,3,5均为丑数,然后再从2算起,4,5,10均为丑数--直到算到第1500个即可.那么有如下的问题: 如何从算出来的丑数中取出最小的? 如何保证没有计算重复的丑数? 对于第一个问题,可以采用优先队列的方法,即有序的队列,且为升序,每次只需要取出队首元素即可…

Ugly numbers are numbers whose only prime factors are 2, 3 or 5. The sequence1, 2, 3, 4, 5, 6, 8, 9, 10, 12, 15, ... shows the first 11 ugly numbers. By convention, 1 is included.Write a program to find and print the 1500'th ugly number. Input There…

Ugly numbers are numbers whose only prime factors are 2, 3 or 5. The sequence 1, 2, 3, 4, 5, 6, 8, 9, 10, 12, 15, ... shows the first 11 ugly numbers. By convention, 1 is included. Write a program to find and print the 1500’th ugly number. Input Ther…

Ugly Numbers 时间限制:1000 ms  |  内存限制:65535 KB 难度:2 描写叙述 Ugly numbers are numbers whose only prime factors are 2, 3 or 5. The sequence 1, 2, 3, 4, 5, 6, 8, 9, 10, 12, 15, ... shows the first 11 ugly numbers. By convention, 1 is included. Now give you ne…

一.题目大意 本题要求写出前1500个仅能被2,3,5整除的数. 二.题解 最初的想法是从1开始检验该数是否只能被2,3,5整除,方法是这样的,对于一个数,如果它能被2整除,就除以2,如果它能被3整除,就除以3,如果它能被5整除,就除以5,直到不能被2,3,5整除,看结果是不是1,如果是1就满足条件,否则不满足条件.但是第1500个数大约近10亿,显然是1s内不可以完成的. 然后仔细分析发现:满足条件的数是2^x*3^y*5^z,可以转换为这样的定义,定义一个集合,该集合中有元素1,如果x在集合…

Ugly Numbers Descriptions: Ugly numbers are numbers whose only prime factors are 2, 3 or 5. The sequence 1, 2, 3, 4, 5, 6, 8, 9, 10, 12, 15, ... shows the first 11 ugly numbers. By convention, 1 is included. Write a program to find and print the 1500…

题目: Ugly numbers are numbers whose only prime factors are 2, 3 or 5 . The sequence 1, 2, 3, 4, 5, 6, 8, 9, 10, 12, 15, ... shows the first 11 ugly numbers. By convention, 1 is included. Write a program to find and print the 1500’th ugly number. Input…

Problem Description Ugly numbers are numbers whose only prime factors are 2, 3 or 5. The sequence 1, 2, 3, 4, 5, 6, 8, 9, 10, 12, 15, ...shows the first 11 ugly numbers. By convention, 1 is included. Write a program to find and print the 1500’th ugly…

Ugly Numbers 题目 Ugly numbers are numbers whose only prime factors are 2, 3 or 5. The sequence 1, 2, 3, 4, 5, 6, 8, 9, 10, 12, 15, ... shows the first 11 ugly numbers. By convention, 1 is included. Write a program to find and print the 1500'th ugly nu…

A. Bad Ugly Numbers time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output You are given a integer nn (n>0n>0). Find any integer ss which satisfies these conditions, or report that there are no s…

Ugly numbers are numbers whose only prime factors are 2, 3 or 5. The sequence 1, 2, 3, 4, 5, 6, 8, 9, 10, 12, 15, ... shows the first 11 ugly numbers. By convention, 1 is included. Write a program to find and print the 1500'th ugly number. Input Ther…

[题目] 我们把只包含质因子2.3和5的数称作丑数(Ugly Number),例如:2,3,4,5,6,8,9,10,12,15,等,习惯上我们把1当做是第一个丑数.求按从小到大的顺序的第1500个丑数. [分析] 这是一道在网络上广为流传的面试题,据说google曾经采用过这道题. 所谓一个数m是另一个数n的因子,是指n能被m整除,也就是n % m == 0.根据丑数的定义,丑数只能被2.3和5整除.也就是说如果一个数如果它能被2整除,我们把它连续除以2:如果能被3整除,就连续除以3:如果能被…

题意:给出丑数的定义,不能被除2,3,5以外的素数整除的的数称为丑数. 和杭电的那一题丑数一样--这里学的紫书上的用优先队列来做. 用已知的丑数去生成新的丑数,利用优先队列的能够每次取出当前最小的丑数再去生成新的丑数==== 大概这儿的优先队列就充当了dp转移方程里面的那个min的意思@_@ #include<iostream> #include<cstdio> #include<cstring> #include<algorithm> #include&l…

题目大意:只有素因子2,3,5的数叫做丑数.输出第1500个丑数即可. 这个...好吧,直接输出就是了.自己写一个小程序先计算一下,这就是黑盒测试的好处啊,“我们的目标是解决问题,而不是为了写程序而写程序,同时应该保持简单(Kepp It Simple and Stupid, KISS)”,摘自<算法竞赛入门经典>. #include <cstdio> int main() { ; // the number of ugly number int i; ; ; i++) { int…

丑数 丑数是指不能被2,3,5以外的其他素数整除的数.把丑数从小到大排列起来,结果如下: 1,2,3,4,5,6,8,9,10,12,15,… 求第1500个丑数. 提示:从小到大生成各个丑数.最小的丑数是1,对于任意丑数x,2x,3x和5x也是丑数.使用一个优先队列保存已生成的丑数,每次取出最小的丑数,生成3个新的丑数.需要注意,同一个丑数有多种生成方式,所以需要判断一个丑数是否已经生成过. 题目链接:https://vjudge.net/contest/211547#problem/G #i…

题目链接: https://cn.vjudge.net/problem/UVA-136 /*问题 输出第1500个丑数,丑数的定义是不能被2,3,5以外的其他素数整除的数 解题思路 直接硬暴力先试一下发现枚举的时候不知道它能被那个素数整除,况且打很大的素数表依次遍历也不一定能够找到1500个丑数. 那么根据定义,如果x是一个丑数,那么2*x.3*x.5*x也一定是丑数.那么构建一个优先队列,让数值小的优先级最高,加入第一个丑数1, 依次加入三个丑数(数值小的在前面),直到第1500个丑数时结束,…

题意 PDF 分析 用堆和集合维护即可. 时间复杂度\(O(1500 \log n)\) 代码 #include<iostream> #include<cstdio> #include<cstdlib> #include<cmath> #include<set> #include<map> #include<queue> #include<stack> #include<algorithm> #in…

[链接] 我是链接,点我呀:) [题意] 在这里输入题意 [题解] 每个丑数x,都能生成3个丑数2x,3x,5x 则我们以1作为起点. 生成丑数. 每次取出set里面最小的那个数. 然后用它去生成其他的丑数. 加入到set里面. 然后再把set的头元素删掉就好. 取1500次. 不知道生成的哪一个更大,那么每次取最小的就好了,set就是用来做这个事的 每次都取最小的来生成,那么新生成的数字,肯定也是尽可能地小的,所以不会出现取出来的不是第i小的数的情况 [代码] #include <bits/s…

原题链接:http://poj.org/problem?id=1338 优先队列的应用,如下: #include<cstdio> #include<cstdlib> #include<queue> #include<functional> #include<iostream> #include<algorithm> using namespace std; typedef long long ll; ; ll ans[Max_N];…

题目 丑数 设计一个算法,找出只含素因子3,5,7 的第 k 大的数. 符合条件的数如:3,5,7,9,15...... 样例 如果k=4, 返回 9 挑战 要求时间复杂度为O(nlogn)或者O(n) 解题 法一:直接暴力,逐次判断一个数是不是丑数 下面只对其中的奇数判断是否是丑数,加不加奇数都超时. class Solution { /** * @param k: The number k. * @return: The kth prime number as description. */…

打表大军是一股邪恶势力→_→ #include <iostream> #include <cstring> #include <cstdlib> #include <cstdio> #include <cctype> #include <cmath> #include <numeric> #include <algorithm> #include <limits.h> #include <ve…

题意:一个数的质因子能是2, 3, 5, 那么这个数是丑数. 思路: 打表或者递推. 打表: 若该数为丑数,那么一定能被2 或者3, 或者5 整除, 除完之后则为1. #include <iostream> #include <fstream> using namespace std; ,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,…