557. Reverse Words in a String III 最简单的把空白之间的词反转 class Solution { public: string reverseWords(string s) { vector<int> blank; ;i < s.size();i++){ if(s[i] == ' ') blank.push_back(i); } ; int end; ;i < blank.size();i++){ end = blank[i] - ; revers…

题目:reverse words in a string Given an input string, reverse the string word by word. For example,Given s = "the sky is blue",return "blue is sky the". 解析:将字符串中的单词逆序输出 借助一个堆栈,从前向后遍历字符串,遇到空,跳过,直到非空字符,拼接word,等再次遇到空时,得到一个word,加入堆栈, 以此类推,直到…

Given an input string, reverse the string word by word. For example,Given s = "the sky is blue",return "blue is sky the". Update (2015-02-12):For C programmers: Try to solve it in-place in O(1) space. Clarification: What constitutes a…

Reverse Words in a String Given an input string, reverse the string word by word. Example 1: Input: "the sky is blue" Output: "blue is sky the" Example 2: Input: " hello world! " Output: "world! hello" Explanation:…

Given an input string, reverse the string word by word. For example,Given s = "the sky is blue",return "blue is sky the". public class Solution { public String reverseWords(String s) { String afterTrim= s.trim(); String[] split=afterTr…

Given an input string, reverse the string word by word. For example, Given s = "the sky is blue", return "blue is sky the". 解题思路: 本题方法多多,最简单的方式直接按“ ” spilt即可,JAVA实现如下: public String reverseWords(String s) { if (s == null || s.length()…

Given an input string, reverse the string word by word. For example,Given s = "the sky is blue",return "blue is sky the". Update (2015-02-12):For C programmers: Try to solve it in-place in O(1) space. 倒序字符串. 注意使用BufferString,因为如果使用Stri…

Given an input string, reverse the string word by word. For example,Given s = "the sky is blue",return "blue is sky the". Update (2015-02-12):For C programmers: Try to solve it in-place in O(1) space. click to show clarification. Clari…

［抄题］: Given an input string, reverse the string word by word. Example: Input: "the sky is blue", Output: "blue is sky the". [暴力解法]: 时间分析: 空间分析: [优化后]: 时间分析: 空间分析: ［奇葩输出条件］: ［奇葩corner case］: ［思维问题］: 打碎成数组后再添加,居然有看不懂的bug. public class So…

思路: 本题考查的目的并不是使用字符串的函数.方法是两次reverse,先对每个单词先做一次翻转,然后对整个字符串做一次翻转. 需要注意的是去除extra space,并且对全space字符串.以及最后一个单词要做特殊处理. class Solution { public: void reverseWords(string &s) { ; ; ; ; // point to the string with extra space deleted //ignore space at the beg…