[BZOJ4391][Usaco2015 dec]High Card Low Card(贪心) 题面 BZOJ 题解 预处理前缀后缀的结果,中间找个地方合并就好了. #include<iostream> #include<cstdio> #include<cstdlib> #include<cstring> #include<cmath> #include<algorithm> #include<set> using na…

[题解][P3129 USACO15DEC]高低卡(白金)High Card Low Card (Platinum) 考虑贪心. 枚举在第几局改变规则,在改变规则之前,尽量出比它大的最小的牌,在改变规则之后,尽量出最大的比它小的牌.前面记录一个\(f(x)\)后面记录一个\(g(x)\) 此时,你会发现,可能方案选择重复了,怎么办?? 一般人都会放弃,但是这是正确的. 证明如下: 假设我们方案重复了\(1\)次,则必定也有一张多出来的牌.由于不存在相同的牌,则这张多出来的牌,必定比那张重复用的牌…

card card card Time Limit: 8000/4000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 1774    Accepted Submission(s): 792 Problem Description As a fan of Doudizhu, WYJ likes collecting playing cards very much. One day…

card card card Time Limit: 8000/4000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 1230    Accepted Submission(s): 549 Problem Description As a fan of Doudizhu, WYJ likes collecting playing cards very much. One day…

As a fan of Doudizhu, WYJ likes collecting playing cards very much. One day, MJF takes a stack of cards and talks to him: let's play a game and if you win, you can get all these cards. MJF randomly assigns these cards into nn heaps, arranges in a row…

https://vjudge.net/contest/184514#problem/L题意:排成一行的一堆牌,每堆牌都有一定数量的牌,然后每堆牌对应有一个惩罚值.一开始所有的牌都是正面向下的,并且在游戏开始之前可以把第一堆牌移到最后,这个操作可以进行若干次.在那之后,一个人开始依次拿起一堆牌,并且把它们全部正面朝上,之后需要把某些牌翻转到正面向下,翻转的数量就是这堆牌的惩罚值,之后把正面向上的牌翻转加到下一堆进行操作.当遇到当前的正面向上的牌小于当前的牌的惩罚值的时候,游戏结束,可以得到这堆牌以…

题目链接 Problem Description As a fan of Doudizhu, WYJ likes collecting playing cards very much. One day, MJF takes a stack of cards and talks to him: let's play a game and if you win, you can get all these cards. MJF randomly assigns these cards into n…

#include<iostream> #include<deque> #include<memory.h> #include<stdio.h> #include<map> #include<string> #include<algorithm> #include<vector> #include<math.h> #include<stack> #include<queue>…

题意 : 给定两个序列 a 和 b ,保证 a 数列的和 == b数列的和,从头到尾考虑 (a[i] - b[i]) 的前缀和,直到前缀和为负数则无法进行下去,所得的便是a[1~i]的和,现在有一个操作,就是你可以将最前面的a[1] && b[1] 这两个数放到末尾去,问你最少经过多少次这样的操作能够使得去到的a[1~i]的的和是最大的 分析 : 发现因为有 a数列的和 == b数列的和,所以肯定有以某一个数开头使得将所有序列的数全部取完即 sum( a[1~末尾] ),我们先构造出 su…

题目链接 感谢 http://blog.csdn.net/txgang/article/details/77568491 以下供参考 getchar读入法 2683MS FastIO法 MX=1e2 561MS MX=1e3 436MS MX=1e4 499MS MX=1e5 452MS MX=1e6 483MS MX=1e7 499MS #include<bits/stdc++.h> using namespace std; typedef long long LL; namespace F…