Given a non negative integer number num. For every numbers i in the range 0 ≤ i ≤ num calculate the number of 1's in their binary representation and return them as an array. Example: For num = 5 you should return [0,1,1,2,1,2]. Follow up: It is very…

原题链接在这里:https://leetcode.com/problems/counting-bits/ 题目: Given a non negative integer number num. For every numbers i in the range 0 ≤ i ≤ num calculate the number of 1's in their binary representation and return them as an array. Example:For num = 5…

Question Given a non negative integer number num. For every numbers i in the range 0 ≤ i ≤ num calculate the number of 1's in their binary representation and return them as an array. Example: For num = 5 you should return [0,1,1,2,1,2]. Follow up: It…

Leetcode之动态规划(DP)专题-338. 比特位计数(Counting Bits) 给定一个非负整数 num.对于 0 ≤ i ≤ num 范围中的每个数字 i ,计算其二进制数中的 1 的数目并将它们作为数组返回. 示例 1: 输入: 2 输出: [0,1,1] 示例 2: 输入: 5 输出: [0,1,1,2,1,2] 进阶: 给出时间复杂度为O(n*sizeof(integer))的解答非常容易.但你可以在线性时间O(n)内用一趟扫描做到吗? 要求算法的空间复杂度为O(n). 你能…

Counting Bits Given a non negative integer number num. For every numbers i in the range 0 ≤ i ≤ num calculate the number of 1's in their binary representation and return them as an array. Example:For num = 5 you should return [0,1,1,2,1,2]. Follow up…

lc 338 Counting Bits 338 Counting Bits Given a non negative integer number num. For every numbers i in the range 0 ≤ i ≤ num calculate the number of 1's in their binary representation and return them as an array. Example: For num = 5 you should retur…

leetcode:Reverse Bits 本题目收获 移位(<<  >>), 或(|),与(&)计算的妙用 题目: Reverse bits of a given 32 bits unsigned integer.For example, given input 43261596 (represented in binary as 00000010100101000001111010011100), return 964176192 (represented in bin…

338.Counting Bits - Medium Given a non negative integer number num. For every numbers i in the range 0 ≤ i ≤ num calculate the number of 1's in their binary representation and return them as an array. Example: For num = 5 you should return [0,1,1,2,1…

最近准备刷 leetcode  做到了一个关于位运算的题记下方法 int cunt = 0; while(temp) { temp = temp&(temp - 1);  //把二进制最左边那个1变为零 count++;   //统计1的个数 } 同理把位二进制坐左边那个0变为1 就可以  temp = temp|(temp + 1)…

leetcode是求当前所有数的二进制中1的个数,剑指offer上是求某一个数二进制中1的个数 https://www.cnblogs.com/grandyang/p/5294255.html 第三种方法,利用奇偶性找规律 class Solution { public: vector<int> countBits(int num) { vector<}; ;i <= num;i++){ == ) result.push_back(result[i/]); else result.…

Given a non negative integer number num. For every numbers i in the range 0 ≤ i ≤ num calculate the number of 1’s in their binary representation and return them as an array. Example: For num = 5 you should return [0,1,1,2,1,2]. Follow up: It is very…

问题描述:给出一个非负整数num,对[0, num]范围内每个数都计算它的二进制表示中1的个数 Example:For num = 5 you should return [0,1,1,2,1,2] 思路:该题属于找规律题,令i从0开始,设f(i)为i对应二进制表示中1的个数,写几对对应值就出来了. 很明显,规律就是[0, 1)部分各个值加1就构成了[1, 2)部分,[0, 2)部分各个值加1就构成了[2, 4)部分,[0, 4)部分各个值加1就构成了[4, 8)部分. 以此类推. 原因也很显然…

附上:题目地址:https://leetcode-cn.com/problems/counting-bits/submissions/ 1:题目: 给定一个非负整数 num.对于 0 ≤ i ≤ num 范围中的每个数字 i ,计算其二进制数中的 1 的数目并将它们作为数组返回. 示例 1: 输入: 2 输出: [0,1,1]示例 2: 输入: 5 输出: [0,1,1,2,1,2]进阶: 给出时间复杂度为O(n*sizeof(integer))的解答非常容易.但你可以在线性时间O(n)内用一趟…

1. Description Given a non negative integer number num. For every numbers i in the range 0 ≤ i ≤ num calculate the number of 1's in their binary representation and return them as an array. Example: For num = 5 you should return [0,1,1,2,1,2]. 2. Answ…

introduction: Given a non negative integer number num. For every numbers i in the range 0 ≤ i ≤ num calculate the number of 1's in their binary representation and return them as an array. Example:For num = 5 you should return [0,1,1,2,1,2]. Follow up…

题目描述: Given a non negative integer number num. For every numbers i in the range 0 ≤ i ≤ num calculate the number of 1's in their binary representation and return them as an array. Example:For num = 5 you should return [0,1,1,2,1,2]. Follow up: It is…

Given a non negative integer number num. For every numbers i in the range 0 ≤ i ≤ num calculate the number of 1's in their binary representation and return them as an array. Example: For num = 5 you should return [0,1,1,2,1,2]. Follow up: It is very…

题目描述: 给定一个数字n,统计0-n之间的数字二进制的1的个数,并用数组输出 例子: For num = 5 you should return [0,1,1,2,1,2]. 要求: 算法复杂复o(n) 空间复杂度o(n) 原文描述: Given a non negative integer number num. For every numbers i in the range 0 ≤ i ≤ num calculate the number of 1's in their binary r…

1.题目描述 2.问题分析 利用bitset. 3 代码 vector<int> countBits(int num) { vector<int> v; ; i <= num; i++){ bitset<> b(i); v.push_back( b.count() ); } return v; }…

原题 Given a non negative integer number num. For every numbers i in the range 0 ≤ i ≤ num calculate the number of 1's in their binary representation and return them as an array. Example: For num = 5 you should return [0,1,1,2,1,2]. Follow up: It is ve…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 日期 题目描述 Given a non negative integer number num. For every numbers i in the range 0 ≤ i ≤ num calculate the number of 1's in their binary representation and return them as an a…

Reverse bits of a given 32 bits unsigned integer. For example, given input 43261596 (represented in binary as 00000010100101000001111010011100), return 964176192 (represented in binary as00111001011110000010100101000000). Follow up:If this function i…

题目链接:hdu 5106 Bits Problem 题目大意:给定n和r,要求算出[0,r)之间全部n-onebit数的和. 解题思路:数位dp,一个ct表示个数,dp表示和,然后就剩下普通的数位dp了.只是貌似正解是o(n)的算法.可是n才 1000.用o(n^2)的复杂度也是够的. #include <cstdio> #include <cstring> #include <algorithm> using namespace std; typedef long…

https://leetcode.com/problems/counting-bits/ 给定一个非负数n,输出[0,n]区间内所有数的二进制形式中含1的个数 Example: For num = 5 you should return [0,1,1,2,1,2]. 注意fellow up部分,题目说了你要是一个个无脑去遍历输出是不ok的,直接用某些内置函数也是不行的 解题思路 实在没思路就看看hint部分 找张纸,多写几个数,包括: 1.数(十进制) 2.数(二进制) 3.二进制中1的个数 图…

Reverse Bits Reverse bits of a given 32 bits unsigned integer. For example, given input 43261596 (represented in binary as 00000010100101000001111010011100), return 964176192 (represented in binary as 00111001011110000010100101000000). Follow up: If…

Given a non negative integer number num. For every numbers i in the range 0 ≤ i ≤ num calculate the number of 1's in their binary representation and return them as an array. Example:For num = 5 you should return [0,1,1,2,1,2]. From: 1. Naive Solution…

Reverse Bits Reverse bits of a given 32 bits unsigned integer. For example, given input 43261596 (represented in binary as 00000010100101000001111010011100), return 964176192 (represented in binary as00111001011110000010100101000000). Follow up:If th…

Given a non negative integer number num. For every numbers i in the range 0 ≤ i ≤ num calculate the number of 1's in their binary representation and return them as an array. Example 1: Input: 2 Output: [0,1,1] Example 2: Input: 5 Output: [0,1,1,2,1,2…

题意:给定一个无符号32位整数,将其二进制形式左右反置,再以整型返回. 思路:循环32轮,将n往右挤出一位就补到ans的尾巴上. class Solution { public: uint32_t reverseBits(uint32_t n) { ; uint32_t ans = ; int i; ; i<; i++ ) { ans <<= ; ) ans |= ; n >>=; } return ans; } }; Reverse Bits…

Reverse bits of a given 32 bits unsigned integer. For example, given input 43261596 (represented in binary as 00000010100101000001111010011100), return 964176192 (represented in binary as00111001011110000010100101000000). Follow up:If this function i…