1030 Travel Plan Dijkstra+dfs】的更多相关文章

和1018思路如出一辙,先求最短路径,再dfs遍历 #include <iostream> #include <cstdio> #include <vector> #include<algorithm> using namespace std; ][], c[][];// distence cost vector<];//到达当前节点的前一个节点 vector<vector<int> > st; //最短距离的路径 vector…
1030 Travel Plan (30 分) A traveler's map gives the distances between cities along the highways, together with the cost of each highway. Now you are supposed to write a program to help a traveler to decide the shortest path between his/her starting ci…
(一)题意 题目链接:https://www.patest.cn/contests/pat-a-practise/1030 1030. Travel Plan (30) A traveler's map gives the distances between cities along the highways, together with the cost of each highway. Now you are supposed to write a program to help a tra…
1030 Travel Plan (30)(30 分) A traveler's map gives the distances between cities along the highways, together with the cost of each highway. Now you are supposed to write a program to help a traveler to decide the shortest path between his/her startin…
1030 Travel Plan (30 分)   A traveler's map gives the distances between cities along the highways, together with the cost of each highway. Now you are supposed to write a program to help a traveler to decide the shortest path between his/her starting…
1030. Travel Plan (30) A traveler's map gives the distances between cities along the highways, together with the cost of each highway. Now you are supposed to write a program to help a traveler to decide the shortest path between his/her starting cit…
#include<bits/stdc++.h> using namespace std; ; const int inf=0x3f3f3f3f; int mp[N][N]; bool vis[N]; int dis[N]; int n,m,s,D; int cost[N][N]; vector<int>path[N]; void Dijkstra() { fill(vis,vis+N,false); fill(dis,dis+N,inf); ;i<n;i++) dis[i]=…
题目 A traveler's map gives the distances between cities along the highways, together with the cost of each highway. Now you are supposed to write a program to help a traveler to decide the shortest path between his/her starting city and the destinatio…
题意: 输入N,M,S,D(N,M<=500,0<S,D<N),接下来M行输入一条边的起点,终点,通过时间和通过花费.求花费最小的最短路,输入这条路径包含起点终点,通过时间和通过花费. trick: 找了半小时bug终于发现是给dis数组赋初值时范围是1~N,这道题点是从0~N-1的,故初次只通过了第0组数据,初始化改一下边界即可AC. AAAAAccepted code: #define HAVE_STRUCT_TIMESPEC #include<bits/stdc++.h>…
A traveler's map gives the distances between cities along the highways, together with the cost of each highway. Now you are supposed to write a program to help a traveler to decide the shortest path between his/her starting city and the destination.…