解决:JavaScript 在函数中使用Ajax获取的值作为函数的返回值,结果无法获取到返回值 原因:ajax默认使用异步方式,要将异步改为同步方式 案例:通过区域ID,获取该区域下所有的学校 var School = new Object(); //保存区下面所有学校 School.GetAllInArea = function (areaId) { var returnData; $.ajax({ url: "/Area/Home/Schools/" + areaId, type:…
在IDEA中使用JDBC获取数据库连接时,有时会报错Sat Dec 19 19:32:18 CST 2020 WARN: Establishing SSL connection without server's identity verification is not recommended. According to MySQL 5.5.45+, 5.6.26+ and 5.7.6+ requirements SSL connection must be established by defa…
在VUE开发时,数据可以使用jquery和vue-resource来获取数据.在获取数据时,一定需要给一个数据初始值. 看下例: <script type="text/javascript"> new Vue({ el:'#app', data:{data:""}, created:function(){ var url="json.jsp"; var _self=this; $.get(url,function(data){ _se…
select @From, @To, EffectiveDate, GETDATE(), Rate from Config_Currency_ExchangeRate_Temp where EffectiveDate not in ( select EffectiveDate from Config_Currency_ExchangeRate where EffectiveDate >=@BeginTime and EffectiveDate <=@EndTime and CIDFrom =…