Hardwood Species Time Limit: 10000MS   Memory Limit: 65536K Total Submissions: 17986   Accepted: 7138 Description Hardwoods are the botanical group of trees that have broad leaves, produce a fruit or nut, and generally go dormant in the winter.  Amer…

题目链接: id=2418">http://poj.org/problem?id=2418 Hardwood Species Time Limit: 10000MS   Memory Limit: 65536K Total Submissions: 17511   Accepted: 6949 Description Hardwoods are the botanical group of trees that have broad leaves, produce a fruit or n…

<题目链接> 题目大意: 给你一堆字符串,让你按字典序输出他们出现的频率. 解题分析: 首先,这是Trie数词频统计的题目,以Trie树的边储存字母,节点存储以该节点结尾的链所代表的字符串的数量,最后用dfs寻找Trie树中所有的单词,下面代码是用数组实现的Trie树.当然,本题也可用快排或者map直接水过. #include<cstdio> #include<cstring> #include<iostream> #include<algorithm…

解题报告 Tire树. #include <iostream> #include <cstring> #include <cstdio> #include <algorithm> using namespace std; struct node { int v; node *next[256]; }; int cnt=0,q; char ch[100],str1[100]; node *newnode() { node *p=new node; p->…

                                                 Hardwood Species Time Limit: 10000MS   Memory Limit: 65536K Total Submissions: 16056   Accepted: 6418 Description Hardwoods are the botanical group of trees that have broad leaves, produce a fruit or n…

职务地址:id=2418">POJ 2418 通过这个题查了大量资料..知道了非常多曾经不知道的东西. . .. 在代码中凝视说明吧. 代码例如以下: #include <iostream> #include <cstdio> #include <string> #include <cstring> #include <stdlib.h> #include <math.h> #include <ctype.h&g…

1.输入若干行树名,输入结束后,按字典序输出树名及其所占百分比. 2.多种方法:map,trie,BST 3. map: #include<iostream> #include<stdio.h> #include<string> #include<map> using namespace std; int main(){ map<string,int>h; string s; int n; n=; while(getline(cin,s)){ +…

题目:http://poj.org/problem?id=2418 在poj 上交题总是有各种错误,再次感叹各个编译器. c++ AC代码,G++为超时,上代码: #include<cstdio> #include<string> #include<map> using namespace std; ]; int main() { map<string,int>mp; map<string,int>::iterator iter;//声明迭代器…

题目传送门 题意:输入一大堆字符串,问字典序输出每个字符串占的百分比 分析:二叉搜索树插入,然后中序遍历就是字典序,这里root 被new出来后要指向NULL,RE好几次.这题暴力sort也是可以过的... //#include <bits/stdc++.h> #include <cstdio> #include <cstring> #include <iostream> using namespace std; struct BST { char name…

#include <stdio.h> #include <stdlib.h> #include <math.h> #include <string.h> typedef struct AVLTree{ char name[31]; int nCount; int nHeight; struct AVLTree* pLeft; struct AVLTree* pRight; }AVLTree; int Max( int a, int b ); int Heig…