P2866 [USACO06NOV]糟糕的一天Bad Hair Day 奶牛题里好多单调栈..... 维护一个单调递减栈,存每只牛的高度和位置,顺便统计一下答案. #include<iostream> #include<cstdio> #include<cstring> using namespace std; #define N 80010 int n,tp,q[N],h[N]; long long ans; int main(){ scanf("%d&qu…

P2866 [USACO06NOV]糟糕的一天Bad Hair Day 题意翻译 农夫约翰有N (N \leq 80000)N(N≤80000)头奶牛正在过乱头发节.每一头牛都站在同一排面朝东方,而且每一头牛的身高为h_ihi​.第NN头牛在最前面,而第11头牛在最后面. 对于第ii头牛前面的第jj头牛,如果h_i>h_{i+1}hi​>hi+1​并且h_i>h_{i+2}hi​>hi+2​ \cdots⋯ h_i>h_jhi​>hj​,那么认为第ii头牛可以看到第i+…

P2866 [USACO06NOV]糟糕的一天Bad Hair Day 75通过 153提交 题目提供者洛谷OnlineJudge 标签USACO2006云端 难度普及/提高- 时空限制1s / 128MB 提交  讨论  题解 最新讨论更多讨论 题目标题 题目描述 Some of Farmer John's N cows (1 ≤ N ≤ 80,000) are having a bad hair day! Since each cow is self-conscious about her…

P2866 [USACO06NOV]糟糕的一天Bad Hair Day 题目描述 Some of Farmer John's N cows (1 ≤ N ≤ 80,000) are having a bad hair day! Since each cow is self-conscious about her messy hairstyle, FJ wants to count the number of other cows that can see the top of other cow…

题目描述 Some of Farmer John's N cows (1 ≤ N ≤ 80,000) are having a bad hair day! Since each cow is self-conscious about her messy hairstyle, FJ wants to count the number of other cows that can see the top of other cows' heads. Each cow i has a specified…

题意:给你一个序列,问将序列倒过来后,对于每个点,在再碰到第一个比它大的点之前,有多少比它小的? 求出比它小的个数的和 样例: 610374122 output: 5 倒序后:2    12    4    7    3   10   6 答案:   0     1     0     1    0     3    0 因此最终输出1+1+3=5 虽然是单调栈裸题(打完暴力才刚看出来) 不过我还是坚持写了暴力(明明是刚开始没思路) #include<cstdio> #include<i…

题目描述 Some of Farmer John's N cows (1 ≤ N ≤ 80,000) are having a bad hair day! Since each cow is self-conscious about her messy hairstyle, FJ wants to count the number of other cows that can see the top of other cows' heads. Each cow i has a specified…

https://www.luogu.org/problem/show?pid=2866 题目描述 Some of Farmer John's N cows (1 ≤ N ≤ 80,000) are having a bad hair day! Since each cow is self-conscious about her messy hairstyle, FJ wants to count the number of other cows that can see the top of o…

链接:https://ac.nowcoder.com/acm/contest/984/A 来源:牛客网 题目描述 Some of Farmer John's N cows (1 ≤ N ≤ 80,000) are having a bad hair day! Since each cow is self-conscious about her messy hairstyle, FJ wants to count the number of other cows that can see the…

传送门 这是一道典型的单调栈. 题意理解 先来理解一下题意(原文翻译得有点问题). 其实就是求对于序列中的每一个数i,求出i到它右边第一个大于i的数之间的数字个数c[i].最后求出和. 首先可以暴力求解,时间复杂度o(n^2)显然TLE. 然后就是用单调栈来做. 单调栈 单调栈就是维护一个栈,使得栈中的元素是单调的(递增/递减). 假设是递减——对于每一个新来的元素,把栈顶大于这个元素的每一个数字全部弹出,最后把这个元素加进去. (如果栈为空,直接加入) 单调栈有什么用呢? 单调递增栈能以o(n…