姿势就是力量啊! 第一次意识到long long 比 int要慢很多.当时想到了各种优化仍然TLE,最后也没A出来,就是用了long long #include <cstdio> #include <algorithm> #include <cstring> #include <ctype.h> #include <cstdlib> #include <stack> #include <set> #include <…

N! Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 262144/262144 K (Java/Others) Total Submission(s): 64256    Accepted Submission(s): 18286 Problem Description Given an integer N(0 ≤ N ≤ 10000), your task is to calculate N!   Input One N in…

E - 5 Time Limit:1500MS     Memory Limit:262144KB     64bit IO Format:%I64d & %I64u Submit Status Practice HDU 5391 Description Tina Town is a friendly place. People there care about each other. Tina has a ball called zball. Zball is magic. It grows…

水题 /* * Author : ben */ #include <cstdio> #include <cstdlib> #include <cstring> #include <cmath> #include <ctime> #include <iostream> #include <algorithm> #include <queue> #include <set> #include <m…

1040水题; These days, I am thinking about a question, how can I get a problem as easy as A+B? It is fairly difficulty to do such a thing. Of course, I got it after many waking nights.Give you some integers, your task is to sort these number ascending (…

题意:判断一些数里有最大因子的数 水题,省赛即将临近,高效的代码风格需要养成,为了简化代码,以后可能会更多的使用宏定义,但是通常也只是快速拿下第一道水题,涨自信.大部分的代码还是普通的形式,实际上能简化的部分也不太多 #include<iostream> #include<cstring> #include<cmath> #include<cstdio> using namespace std; #define for0n for(i=0;i<n;i+…

/* 对于只会弗洛伊德的我,迪杰斯特拉有点不是很理解,后来发现这主要用于单源最短路,稍稍明白了点,不过还是很菜,这里只是用了邻接矩阵 套模板,对于邻接表暂时还,,,没做题,后续再更新.现将这题贴上,应该是迪杰斯特拉最水的题没有之一.纯模板 找到距离起点最近的点,以此点为中间点进行更新,找到了在进行下一个点. */ 题目大意: 搬东西很累,想省力,给你几个点和点之间的距离:标准题型: #include<stdio.h> #include <iostream> #include<…

题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=5162 题解:看了半天以为测试用例写错了.这题玩文字游戏.它问的是当前第i名是原数组中的第几个. #include<stdio.h> #include<iostream> #include<string.h> #include <stdlib.h> #include<math.h> #include<algorithm> #include…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=3357 #include <cstdio> #include <cmath> #include <algorithm> #include <iostream> #include <cstring> #include <queue> #include <vector> #define maxn 250 #define maxe 1…

题意:最大困难=距离 / 相邻时间 #include<cstring> #include<cstdio> #include<cmath> #define ll double ll num[][]; #define max(a, b) (a)>(b)?(a):(b) int main() { int t; scanf("%d", &t); while (t--) { int n; scanf("%d", &n)…