Binary Tree Maximum Path Sum Given a binary tree, find the maximum path sum. The path may start and end at any node in the tree. For example: Given the below binary tree, 1 / \ 2 3 Return 6. 递归求解. maxPathSum(root)跟maxPathSum(root.left)和maxPathSum(roo…

Binary Tree Maximum Path SumGiven a binary tree, find the maximum path sum. The path may start and end at any node in the tree. For example:Given the below binary tree, 1      / \     2   3 SOLUTION 1: 计算树的最长path有2种情况: 1. 通过根的path. (1)如果左子树从左树根到任何一个N…

题目: Binary Tree Maximum Path Sum Given a binary tree, find the maximum path sum. The path may start and end at any node in the tree. For example:Given the below binary tree, 1 / \ 2 3 Return 6. 节点可能为负数,寻找一条最路径使得所经过节点和最大.路径可以开始和结束于任何节点但是不能走回头路. 这道题虽然看…

Given a binary tree, find the maximum path sum. The path may start and end at any node in the tree. For example:Given the below binary tree, 1 / \ 2 3 Return 6. 这道求二叉树的最大路径和是一道蛮有难度的题,难就难在起始位置和结束位置可以为任意位置,我当然是又不会了,于是上网看看大神们的解法,看了很多人的都没太看明白,最后发现了网友Yu's…

1.题目说明 Given a binary tree, find the maximum path sum.   The path may start and end at any node in the tree.   For example: Given the below binary tree,   1 / \ 2 3 Return 6.   2.解法分析: leetcode中给出的函数头为:int maxPathSum(TreeNode *root) 给定的数据结构为: Definit…

偶然在面试题里面看到这个题所以就在Leetcode上找了一下,不过Leetcode上的比较简单一点. 题目: Given a binary tree, find the maximum path sum. For this problem, a path is defined as any sequence of nodes from some starting node to any node in the tree along the parent-child connections. Th…

Given a binary tree, find the maximum path sum. The path may start and end at any node in the tree. For example:Given the below binary tree, 1 / \ 2 3 Return 6. 题目意思很简单,就是给定一棵二叉树,求最大路径和.path 可以从任意 node 开始,到任意 node 结束. 这道题在 LeetCode 上的通过率只有 20% 多一点,并被…

原题地址:https://oj.leetcode.com/problems/binary-tree-maximum-path-sum/ 题意: Given a binary tree, find the maximum path sum. The path may start and end at any node in the tree. For example:Given the below binary tree, 1 / \ 2 3 Return 6. 解题思路:这道题是在树中寻找一条路…

Given a binary tree, find the maximum path sum. The path may start and end at any node in the tree. For example:Given the below binary tree, 1 / \ 2 3 Return6. 思路:题目中说明起始节点可以是任意节点,所以,最大的路径和不一样要经过root,可以是左子树中某一条,或者是右子树中某一条,当然也可能是经过树的根节点root的.递归式是应该是这三…

题意:给一棵二叉树,要求找出任意两个节点(也可以只是一个点)的最大路径和,至少1个节点,返回路径和.(点权有负的.) 思路:DFS解决,返回值是,经过从某后代节点上来到当前节点且路径和最大的值.要注意如果子树传来的如果是负值,是可以同时丢弃的,但至少要将当前节点的val更新答案. /** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right;…