Large Division Given two integers, a and b, you should check whether a is divisible by b or not. We know that an integer a is divisible by an integer b if and only if there exists an integer c such that a = b * c. Input Input starts with an integer T…

题意:给出一个大数,这个大数由两个素数相乘得到,让我们判断是否其中一个素数比L要小,如果两个都小,输出较小的那个. 分析:大数求余的方法:针对题目中的样例,143 11,我们可以这样算,1 % 11 = 1:      1×10 + 4 % 11 = 3:      3×10 + 3 % 11 = 0;我们可以把大数拆成小数去计算,同余膜定理保证了这个算法的这正确性,而且我们将进制进行一定的扩大也是正确的. 注意:素数打标需要优化,否则超时.   进制需要适当,100和1000都可以,10进制超…

1214 - Large Division Given two integers, a and b, you should check whether a is divisible by b or not. We know that an integer a is divisible by an integer b if and only if there exists an integer c such that a = b * c. Input Input starts with an in…

1214 - Large Division   PDF (English) Statistics Forum Time Limit: 1 second(s) Memory Limit: 32 MB Given two integers, a and b, you should check whether a is divisible by b or not. We know that an integer a is divisible by an integer b if and only if…

Given two integers, a and b, you should check whether a is divisible by b or not. We know that an integer a is divisible by an integer b if and only if there exists an integer c such that a = b * c. Input Input starts with an integer T (≤ 525), denot…

简单大数模拟题: #include<bits/stdc++.h> using namespace std; typedef long long ll; string Num; vector<ll> Big; ll MOD(vector<ll> Big, ll m) { ll ret = 0; for(int i = 0; i < Big.size(); ++i) { ret = ret * 10 + Big[i]; ret = ret % m; } return…

题意: 项的自幂级数求和为 11 + 22 + 33 + - + 1010 = 10405071317. 求如下一千项的自幂级数求和的最后10位数字:11 + 22 + 33 + - + 10001000. 思路: 求最后十位数字 % 1010 即可. 对于快速幂中数据溢出的问题,有两种解决方法: 1. 方法一:对于两个数 x y,现在想求 x * y % MOD,可以将 x 表示成 a * DIGS + b,y 表示成 c * DIGS + d,x * y % MOD 则等价与 ( a * c…

题目链接:http://poj.org/problem?id=2635 题目分析: http://blog.csdn.net/lyy289065406/article/details/6648530…

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Problem Descripton Two planets named Haha and Xixi in the universe and they were created with the universe beginning. There is 73 days in Xixi a year and 137 days in Haha a year. Now you know the days N after Big Bang, you need to answer whether it i…