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Palindrome Partitioning Total Accepted: 21056 Total Submissions: 81036My Submissions Given a string s, partition s such that every substring of the partition is a palindrome. Return all possible palindrome partitioning of s. For example, given s = "a…
Given a string s, partition s such that every substring of the partition is a palindrome. Return all possible palindrome partitioning of s. Example: Input: "aab" Output: [ ["aa","b"], ["a","a","b"…
Palindrome Partitioning 题解 原创文章,拒绝转载 题目来源:https://leetcode.com/problems/palindrome-partitioning/description/ Description Given a string s, partition s such that every substring of the partition is a palindrome. Return all possible palindrome partitio…
Given a string s, partition s such that every substring of the partition is a palindrome. Return all possible palindrome partitioning of s. For example, given s = "aab",Return [ ["aa","b"], ["a","a","…
1 Palindrome Partitioning 问题来源:Palindrome Partitioning 该问题简单来说就是给定一个字符串,将字符串分成多个部分,满足每一部分都是回文串,请输出所有可能的情况. 该问题的难度比较大,很可能第一次遇到没有思路,这很正常.下面我们一点点分析,逐步理清思路.先不考虑所有的情况,针对一个符合条件的划分,每一部分都是一个回文子串,而且各部分的长度不固定.也即每一部分都是原始字符串的一个子串,且满足回文条件.所有的划分都满足上述条件,所以这就启发我们首先判…
131. Palindrome Partitioning substr使用的是坐标值,不使用.begin()..end()这种迭代器 使用dfs,类似于subsets的题,每次判断要不要加入这个数 start每次是起始的位置,判断当前位置到起始位置是不是回文 class Solution { public: vector<vector<string>> partition(string s) { vector<vector<string> > result;…
1 Palindrome Partitioning 问题来源:Palindrome Partitioning 该问题简单来说就是给定一个字符串,将字符串分成多个部分,满足每一部分都是回文串,请输出所有可能的情况. 该问题的难度比较大,很可能第一次遇到没有思路,这很正常.下面我们一点点分析,逐步理清思路.先不考虑所有的情况,针对一个符合条件的划分,每一部分都是一个回文子串,而且各部分的长度不固定.也即每一部分都是原始字符串的一个子串,且满足回文条件.所有的划分都满足上述条件,所以这就启发我们首先判…
Given a string s, partition s such that every substring of the partition is a palindrome. Return the minimum cuts needed for a palindrome partitioning of s. For example, given s = "aab",Return 1 since the palindrome partitioning ["aa",…
Given a string s, partition s such that every substring of the partition is a palindrome. Return the minimum cuts needed for a palindrome partitioning of s. For example, given s = "aab",Return 1 since the palindrome partitioning ["aa",…
Palindrome Partitioning II Given a string s, partition s such that every substring of the partition is a palindrome. Return the minimum cuts needed for a palindrome partitioning of s. For example, given s = "aab",Return 1 since the palindrome pa…
Palindrome Partitioning Given a string s, partition s such that every substring of the partition is a palindrome. Return all possible palindrome partitioning of s. For example, given s = "aab",Return [ ["aa","b"], ["a&qu…
Given a string s, partition s such that every substring of the partition is a palindrome. Return the minimum cuts needed for a palindrome partitioning of s. For example, given s = "aab",Return 1 since the palindrome partitioning ["aa",…
Given a string s, partition s such that every substring of the partition is a palindrome. Return the minimum cuts needed for a palindrome partitioning of s. Example: Input: "aab" Output: 1 Explanation: The palindrome partitioning ["aa"…
Given a string s, partition s such that every substring of the partition is a palindrome. Return all possible palindrome partitioning of s. Example: Input: "aab" Output: [ ["aa","b"], ["a","a","b"…
Given a string s, partition s such that every substring of the partition is a palindrome. Return the minimum cuts needed for a palindrome partitioning of s. For example, given s = "aab", Return 1 since the palindrome partitioning ["aa"…
Given a string s, partition s such that every substring of the partition is a palindrome. Return all possible palindrome partitioning of s. For example, given s = "aab",Return [    ["aa","b"],    ["a","a",…
[题目] Given a string s, partition s such that every substring of the partition is a palindrome. Return all possible palindrome partitioning of s. For example, given s = "aab", Return [ ["aa","b"], ["a","a",…
方法一:DFS递归,判断每一个是否为回文数 1,首先要有一个判断字符串是否是回文的函数.容易实现,字符串从两边同时往中间走,看字符是否相同; 2,深度优先搜索思想对字符串进行遍历.得到结果.例如,s = "abacd"; 需要对“a”“ad”“aba”“abac”“abacd”进行深度优先搜索.深度搜索的过程如下:先选“a”,发现“a”是回文,则深度遍历“bacd”,继续深度遍历,“b”也是回文,深度遍历“acd”,继续下去; 同时,深度遍历“a”的同时,也需要深度遍历“ab”,“ab…
求次数的问题一般用DP class Solution(object): def minCut(self, s): """ :type s: str :rtype: int """ n = len(s) maxInt = 2147483647 cuts = [maxInt for x in range(n)] p = self.palinTable(s) for i in range(n): temp = maxInt if p[0][i] ==…
https://leetcode.com/problems/palindrome-partitioning/ Given a string s, partition s such that every substring of the partition is a palindrome. Return all possible palindrome partitioning of s. For example, given s = "aab",Return [ ["aa&qu…
题目描述 给定一个字符串 s,将 s 分割成一些子串,使每个子串都是回文串. 返回符合要求的最少分割次数. 示例: 输入: "aab" 输出: 1 解释: 进行一次分割就可将 s 分割成 ["aa","b"] 这样两个回文子串. 解题思路 动态规划思想.从最后一个字符开始向前遍历,每次判断以当前字符为首字母依次到最后字符的子字符串是否为回文串,若是则更新包含当前回文串的最小回文串数.具体想法可参考leetcode之 Palindrome Part…
Given a string s, partition s such that every substring of the partition is a palindrome. Return all possible palindrome partitioning of s. For example, given s = "aab",Return [ ["aa","b"], ["a","a","…
Given a string s, partition s such that every substring of the partition is a palindrome. Return all possible palindrome partitioning of s. For example, given s = "aab",Return [ ["aa","b"], ["a","a","…
LeetCode:Palindrome Partitioning 题目如下:(把一个字符串划分成几个回文子串,枚举所有可能的划分) Given a string s, partition s such that every substring of the partition is a palindrome. Return all possible palindrome partitioning of s. For example, given s = "aab",Return [ […
原题地址:https://oj.leetcode.com/problems/palindrome-partitioning-ii/ 题意: Given a string s, partition s such that every substring of the partition is a palindrome. Return the minimum cuts needed for a palindrome partitioning of s. For example, given s = …
原题地址:https://oj.leetcode.com/problems/palindrome-partitioning/ 题意: Given a string s, partition s such that every substring of the partition is a palindrome. Return all possible palindrome partitioning of s. For example, given s = "aab",Return […
Given a string s, partition s such that every substring of the partition is a palindrome. Return all possible palindrome partitioning of s. For example, given s = "aab",Return [    ["aa","b"],    ["a","a",…
Leetcode之回溯法专题-131. 分割回文串(Palindrome Partitioning) 给定一个字符串 s,将 s 分割成一些子串,使每个子串都是回文串. 返回 s 所有可能的分割方案. 示例: 输入: "aab" 输出: [ ["aa","b"], ["a","a","b"] ] 分析:给定一个字符串,要求分割,并且要求分割出来的所有的串是回文串.利用回溯,每次dfs分两…
Given a string s, partition s such that every substring of the partition is a palindrome. Return the minimum cuts needed for a palindrome partitioning of s. For example, given s = "aab", Return 1 since the palindrome partitioning ["aa"…
参考:http://www.cppblog.com/wicbnu/archive/2013/03/18/198565.html 我太喜欢用dfs和回溯法了,但是这些暴力的方法加上剪枝之后复杂度依然是很高,显然不能达到题目的要求. 这个时候应该考虑动态规划,并且要复杂度尽量接近O(n^2)的算法. 下面这个方法更加简洁:自长到短找到回文串后,往后dfs,并记录递归深度表示并更新最小划分数.http://fisherlei.blogspot.com/2013/03/leetcode-palindro…