标题题目地址 1.解题意 求解两个链表的焦点,这个交点并不是焦点的值相等,而是需要交点之后的数据是完全相等的. 落实到java层面,就是交点处的对象是同一个对象即可. ps:我最开始没有读懂题目,然后就开始比较节点的值是否相等,直到示例跑失败了才知道原因. 2.通用解法 public ListNode getIntersectionNode(ListNode headA, ListNode headB) { if(headA!=null && headB!=null){ ListNode…

［抄题］: Write a program to find the node at which the intersection of two singly linked lists begins. For example, the following two linked lists: A: a1 → a2 ↘ c1 → c2 → c3 ↗ B: b1 → b2 → b3 begin to intersect at node c1. Notes: If the two linked lists…

Write a program to find the node at which the intersection of two singly linked lists begins. For example, the following two linked lists: A: a1 → a2 ↘ c1 → c2 → c3 ↗ B: b1 → b2 → b3 begin to intersect at node c1. Notes: If the two linked lists have…

Write a program to find the node at which the intersection of two singly linked lists begins. For example, the following two linked lists: A: a1 → a2 ↘ c1 → c2 → c3 ↗ B: b1 → b2 → b3 begin to intersect at node c1. Notes: If the two linked lists have…

Write a program to find the node at which the intersection of two singly linked lists begins. Notice If the two linked lists have no intersection at all, return null. The linked lists must retain their original structure after the function returns. Y…

此题扩展:链表有环,如何判断相交? 参考资料: 编程判断两个链表是否相交 面试精选:链表问题集锦 题目链接 题目要求: Write a program to find the node at which the intersection of two singly linked lists begins. For example, the following two linked lists: A: a1 → a2 ↘ c1 → c2 → c3 ↗ B: b1 → b2 → b3 begin t…

Write a program to find the node at which the intersection of two singly linked lists begins. For example, the following two linked lists: A: a1 → a2 ↘ c1 → c2 → c3 ↗ B: b1 → b2 → b3 求两个链表开始重合的地方,也就是交叉的地方.. 思路:两个链表从交叉的位置开始,后面的长度是相同的,前面的长度可能相等也可能不同.当前…

题目 两个链表的交叉 请写一个程序,找到两个单链表最开始的交叉节点. 样例 下列两个链表: A: a1 → a2 ↘ c1 → c2 → c3 ↗ B: b1 → b2 → b3 在节点 c1 开始交叉. 注意 如果两个链表没有交叉,返回null. 在返回结果后,两个链表仍须保持原有的结构. 可假定整个链表结构中没有循环. 挑战 需满足 O(n) 时间复杂度,且仅用 O(1) 内存. 解题 尝试用时间复杂度是O(NM),却没有解决,在这个博客看到根据两个链表的特性进行解决. 就如同上图,两个链表…

Intersection of Two Linked Lists Write a program to find the node at which the intersection of two singly linked lists begins. For example, the following two linked lists: A: a1 → a2 ↘ c1 → c2 → c3 ↗ B: b1 → b2 → b3 begin to intersect at node c1. Not…

方法要记住,和判断是不是交叉链表不一样 方法是将两条链表的路径合并,两个指针分别从a和b走不同路线会在交点处相遇 public ListNode getIntersectionNode(ListNode headA, ListNode headB) { if (headA==null||headB==null) return null; /* 本来想用快慢指针做,把其中一个链表收尾相接,然后再用判断循环链表路口的方法 但是觉得这个easy的题目应该不会这么复杂,看了答案却是有更好的方法 求两个链…