题目: Given a string S, find the longest palindromic substring in S. You may assume that the maximum length of S is 1000, and there exists one unique longest palindromic substring. 思路:用Manacher算法得到最大回文子串的长度,得到带#的最大回文子串,用split剔除#后转化成String形式输出即可. public…
int sta = 0; int max = 1; public String longestPalindrome(String s) { /* 判断回文有两种: 1.最大回文子序列求长度: 用动态规划,dp[sta][end] 代表开头为sta.结尾为end的部分最大回文子序列的长度是多少 dp[sta][end] = (s.charAt(sta)==s.charAt(end))?dp[sta+1][end-1]+2:max(dp[sta][end-1],dp[sta+1][end]) 2.最…
问题描述 Given a string S, find the longest palindromic substring in S. You may assume that the maximum length of S is 1000, and there exists one unique longest palindromic substring. 所谓回文字符串,就是一个字符串,从左到右读和从右到左读是完全一样的.比如"a" , "aaabbaaa" 之前…
Given a string s, find the longest palindromic subsequence's length in s. You may assume that the maximum length of s is 1000.Example 1:Input:"bbbab"Output:4One possible longest palindromic subsequence is "bbbb".Example 2:Input:"c…
明天就要上课了,再过几天又要见班主任汇报项目进程了,什么都没做的我竟然有一种迷之淡定,大概是想体验一波熬夜修仙的快乐了.不管怎么说,每天还是要水一篇博文,写一个LeetCode的题才圆满. 题目:Given a string s, find the longest palindromic substring in s. You may assume that the maximum length of s is 1000. Example: Input: "babad" : Out…
题目描述 Given a string S, find the longest palindromic substring in S. You may assume that the maximum length of S is 1000, and there exists one unique longest palindromic substring. 即给定一个字符串,求它的最长回文子串的长度(或者最长回文子串). 解法一 对于一个问题,一定可以找到一个傻的可爱的暴力解法,本题的暴力解法即…
[译+改]最长回文子串(Longest Palindromic Substring) Part II 原文链接在http://leetcode.com/2011/11/longest-palindromic-substring-part-ii.html 原文作者有些地方逻辑上有点小问题,我做了纠正.关于解释时间复杂度上,原作者就只有两句话,我无法理解,特意在此加强了,便于理解. 问题:给定字符串S,求S中的最长回文子串. 在上一篇,我们给出了4种算法,其中包括一个O(N2)时间O(1)空间的算法…