Paint the Grid Reloaded Time Limit: 2000MS   Memory Limit: 65536KB   64bit IO Format: %lld & %llu [Submit]   [Go Back]   [Status] Description Leo has a grid with N rows and M columns. All cells are painted with either black or white initially. Two ce…

题目: Leo has a grid with N rows and M columns. All cells are painted with either black or white initially. Two cells A and B are called connected if they share an edge and they are in the same color, or there exists a cell C connected to both A and B.…

Paint the Grid Reloaded Time Limit: 2 Seconds      Memory Limit: 65536 KB Leo has a grid with N rows and M columns. All cells are painted with either black or white initially. Two cells A and B are called connected if they share an edge and they are…

题目链接:http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemCode=3781 Time Limit: 2 Seconds      Memory Limit: 65536 KB Leo has a grid with N rows and M columns. All cells are painted with either black or white initially. Two cells A and B are calle…

Leo has a grid with N rows and M columns. All cells are painted with either black or white initially. Two cells A and B are called connected if they share an edge and they are in the same color, or there exists a cell C connected to both A and B. Leo…

原题: ZOJ 3781 http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemCode=3781 题意: 给一个n*m的X,O构成的格子,对一个点操作可以使与它相连通的所有一样颜色的格子翻转颜色(X->O或O->X),问给定的矩阵最少操作多少次可以全部变成一样的颜色. 网上思路: 每次操作都将本身所在的连通块与和自己相邻的不同颜色的连通块变成同一种颜色,也就是变成一个连通块了,那么要使n次操作后全部变成一样的颜色,也就是从某点出发到达…

题目链接:http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemCode=3781 Leo has a grid with N rows and M columns. All cells are painted with either black or white initially. Two cells A and B are called connected if they share an edge and they are in…

Paint the Grid Again Time Limit: 2000MS   Memory Limit: 65536KB   64bit IO Format: %lld & %llu [Submit]   [Go Back]   [Status] Description Leo has a grid with N × N cells. He wants to paint each cell with a specific color (either black or white). Leo…

题目链接:http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemId=5268 题目大意:字符一样并且相邻的即为连通.每次可翻转一个连通块X(O)的颜色,问至少改变几次使得图上所有字符都相等. 解题思路: 1) dfs( 建图 ) ,因为翻转的时候每翻转连通块中一个整个连通块都翻转,这样你可以将其看成一个有边相连的无向图,每个边的两个顶点颜色都不一样. 2) bfs( 寻找最优解 ) , 建完图后就需要翻转计算最优解,可以枚举从每一点开始…

思路: 先用DFS缩点,然后BFS找出每个点出发能到达的最长路,取$min$. 注意多组数据,初始化一定要仔细,刚开始存边的$e$忘记初始化,一直WA,调了半个晚上. 一开始和网上的题解对拍$T=1$一直对不出错,后来测了大数据才发现是初始化的问题. #include<queue> #include<vector> #include<cstring> #include<iostream> const int inf=0x7fffffff; ,,,},dy[]…