题解-Roman and Numbers 前置知识: 数位 \(\texttt{dp}\) </> \(\color{#9933cc}{\texttt{Roman and Numbers}}\) 给定 \(n\) 和 \(m\),求将 \(n\) 的各位数字重新排列(不允许有前导 \(0\)),求可以构造几个能被 \(m\) 整除. 数据范围:\(1\le n\le 10^{18}\),\(1\le m\le 100\). 用数位 \(\texttt{dp}\) 代码又短时间又优又好理解,为什…

题目链接: http://codeforces.com/problemset/problem/401/D D. Roman and Numbers time limit per test4 secondsmemory limit per test512 megabytes 问题描述 Roman is a young mathematician, very famous in Uzhland. Unfortunately, Sereja doesn't think so. To make Sere…

D. Roman and Numbers time limit per test 4 seconds memory limit per test 512 megabytes input standard input output standard output Roman is a young mathematician, very famous in Uzhland. Unfortunately, Sereja doesn't think so. To make Sereja change h…

Roman and Numbers time limit per test 4 seconds memory limit per test 512 megabytes input standard input output standard output Roman is a young mathematician, very famous in Uzhland. Unfortunately, Sereja doesn't think so. To make Sereja change his…

You are given two linked lists representing two non-negative numbers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list. Input: (2 -> 4 -> 3) + (5 -> 6 ->…

前言   [LeetCode 题解]系列传送门:  http://www.cnblogs.com/double-win/category/573499.html   1.题目描述 Given a roman numeral, convert it to an integer. Input is guaranteed to be within the range from 1 to 3999. 2. 思路 找到规则即可 罗马数字的表示: I~1 V~5 X~10 L~50 C~100 D~500…

CF401D 题意翻译 将n(n<=10^18)的各位数字重新排列(不允许有前导零) 求 可以构造几个mod m等于0的数字 题目描述 Roman is a young mathematician, very famous in Uzhland. Unfortunately, Sereja doesn't think so. To make Sereja change his mind, Roman is ready to solve any mathematical problem. Afte…

题目: You are given two linked lists representing two non-negative numbers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list. Input: (2 -> 4 -> 3) + (5 -> 6 -&…

题目大意 Description 给定一个数 N(N<1018) , 求有多少个经过 N 重组的数是 M(M≤100) 的倍数. 注意: ①重组不能有前导零; ②重组的数相同, 则只能算一个数. Input 第一行两个数 N , M . Output 输出满足要求的数的个数. Sample Input 223 4 Sample Output 1 题解 状压DP. \(f[i][j]\)中, \(i\)是状态, 表示原数中哪些位已经被新数占用. 因此, 一个Naive的想法就是对于新数的每一位,…

题目: 将罗马数字转换为整数. 解法: 可以参考上一篇数字转换为罗马数字的规则. 代码: class Solution { public: int sym2int(char sym) //罗马数字字符与数字的对应关系 { switch(sym) { ; ; ; ; ; ; ; ; } } int romanToInt(string s) { ]); ; i < s.size(); ++i) { result += sym2int(s[i]); ])) //如果当前字符比上一字符对应的值要大,说明…