LeetCode--Add Strings Question Given two non-negative integers num1 and num2 represented as string, return the sum of num1 and num2. Note: The length of both num1 and num2 is < 5100. Both num1 and num2 contains only digits 0-9. Both num1 and num2 doe…

Given two non-negative numbers num1 and num2 represented as string, return the sum of num1 and num2. Note: The length of both num1 and num2 is < 5100. Both num1 and num2 contains only digits 0-9. Both num1 and num2 does not contain any leading zero.…

原题链接在这里:https://leetcode.com/problems/add-strings/ 题目: Given two non-negative numbers num1 and num2 represented as string, return the sum of num1 and num2. Note: The length of both num1 and num2 is < 5100. Both num1 and num2 contains only digits 0-9.…

这些题目是高精度加法和高精度乘法相关的,复习了一下就做了,没想到难住自己的是C++里面string的用法. 原题地址: 415 Add Strings:https://leetcode.com/problems/add-strings/description/ 67 Add Binary: https://leetcode.com/problems/add-binary/description/ 43 Multiply Strings:https://leetcode.com/problems/…

415. Add Strings Given two non-negative integers num1 and num2 represented as string, return the sum of num1 and num2. Note: The length of both num1 and num2 is < 5100. Both num1 and num2 contains only digits 0-9. Both num1 and num2 does not contain…

problem 415. Add Strings solution: class Solution { public: string addStrings(string num1, string num2) { ; ; ; string res = ""; || j>= || carry) { )?:(num1[i--]-)?:(num2[j--]-')) + carry;//注意运算符的优先级顺序. carry = tmp/; res = to_string(tmp%) + r…

Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. 这道题让我们求两个字符串数字的相乘,输入的两个数和返回的数都是以字符串格式储存的,这样做的原因可能是这样可以计算超大数相乘,可以不受int或long的数值范围的约束,那么我们该如何来计算…

You are given two linked lists representing two non-negative numbers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list. Input: (2 -> 4 -> 3) + (5 -> 6 ->…

415. Add Strings Easy Given two non-negative integers num1 and num2 represented as string, return the sum of num1 and num2. Note: The length of both num1 and num2 is < 5100. Both num1 and num2 contains only digits 0-9. Both num1 and num2 does not con…

原文题目: 447. Add Strings 解题: 字符串的当做整数来做加法,其实就是大数加法的简化版本 思路: 1)考虑不同位数,如"1234"+“45”,需要先处理低两位,再处理num1的高两位 2)考虑进位,相加大于10时就要进位,进位值 = sum/10: 3)考虑最高位的进位,如“5099”+“4987”最后得到了五位的“10086” AC代码: class Solution { public: string addStrings(string num1, string n…