Time Limit: 1000MS Memory Limit: 10000K Description BIT has recently taken delivery of their new supercomputer, a 32 processor Apollo Odyssey distributed shared memory machine with a hierarchical communication subsystem. Valentine McKee's research ad…

MPI Maelstrom Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 4017   Accepted: 2412 Description BIT has recently taken delivery of their new supercomputer, a 32 processor Apollo Odyssey distributed shared memory machine with a hierarchic…

POJ-1502 MPI Maelstrom 迪杰斯特拉+题解 题意 题意:信息传输,总共有n个传输机,先要从1号传输机向其余n-1个传输机传输数据,传输需要时间,给出一个严格的下三角(其实就是对角线之下的不包括对角线的部分)时间矩阵,a[i][j]代表从i向j传输数据需要的时间,并规定数据传输之间并无影响,即第一个传输机可以同时向其余传输机传输数据.求所有所有的机器都收到消息(他们收到消息后也可以传输)所需的最短时间. 解题思路 这个可以用迪杰斯特拉来求第一台机器到其他所有机器传输消息的时间,…

MPI Maelstrom Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 6044   Accepted: 3761 Description BIT has recently taken delivery of their new supercomputer, a 32 processor Apollo Odyssey distributed shared memory machine with a hierarchic…

MPI Maelstrom 总时间限制:  1000ms 内存限制:  65536kB 描述 BIT has recently taken delivery of their new supercomputer, a 32 processor Apollo Odyssey distributed shared memory machine with a hierarchical communication subsystem. Valentine McKee's research advisor…

传送门 MPI Maelstrom Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 5711   Accepted: 3552 Description BIT has recently taken delivery of their new supercomputer, a 32 processor Apollo Odyssey distributed shared memory machine with a hierar…

MPI Maelstrom Time Limit : 2000/1000ms (Java/Other)   Memory Limit : 20000/10000K (Java/Other) Total Submission(s) : 2   Accepted Submission(s) : 1 Problem Description BIT has recently taken delivery of their new supercomputer, a 32 processor Apollo…

POJ 1502 MPI Maelstrom / UVA 432 MPI Maelstrom / SCU 1068 MPI Maelstrom / UVALive 5398 MPI Maelstrom /ZOJ 1291 MPI Maelstrom (最短路径) Description BIT has recently taken delivery of their new supercomputer, a 32 processor Apollo Odyssey distributed shar…

MPI Maelstrom Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 7471   Accepted: 4550 Description BIT has recently taken delivery of their new supercomputer, a 32 processor Apollo Odyssey distributed shared memory machine with a hierarchic…

MPI Maelstrom BIT has recently taken delivery of their new supercomputer, a 32 processor Apollo Odyssey distributed shared memory machine with a hierarchical communication subsystem. Valentine McKee's research advisor, Jack Swigert, has asked her to…

MPI Maelstrom Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 5547   Accepted: 3458 Description BIT has recently taken delivery of their new supercomputer, a 32 processor Apollo Odyssey distributed shared memory machine with a hierarchic…

MPI Maelstrom Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 6499   Accepted: 4036 Description BIT has recently taken delivery of their new supercomputer, a 32 processor Apollo Odyssey distributed shared memory machine with a hierarchic…

题意:表面乍一看output是输出最小值,但仔细研究可以发现,这个最小值是从点1到所有点所花时间的最小值,其实是访问这些节点中的最大值,因为只有访问了最长时间的那个点才算访问了所有点.所以求最短路之后求最大值. #include <iostream> #include <cstring> #include <cstdio> using namespace std; + ; const int inf = 0x3f3f3f3f; int n, mp[maxn][maxn]…

题意 给出图,从点1出发,求到最后一个点的时间. 思路 单源最短路,没什么好说的.注意读入的时候的技巧. 代码 #include <cstdio> #include <cstring> #include <iostream> #include <algorithm> using namespace std; const int INF = 1000000000; const int maxn = 110; int n; int edge[maxn][maxn…

红果果的dijstra算法应用,这里采用邻接表存储图 小插曲:while(scanf("%d",&n))提交时内存超限,改成while(scanf("%d",&n)!=EOF)就AC了,不知道为什么 dijstra算法应用:已知定点为输入,输入图中所有其他点到该定点的最短距离. 具体做法: a.初始时,S只包含源点,即S＝{v},v的距离为0.U包含除v外的其他顶点,即:U={其余顶点},若v与U中顶点u有边,则<u,v>正常有权值,若u…

#include<iostream> #include<cstring> #include<algorithm> #include<iomanip> #include<cmath> #include<cstdio> #include<vector> using namespace std; #define MAXN 101 #define INF 0x3f3f3f3f /* 8:19 8:35 题意理解太慢:在所有最短路路…

Description BIT has recently taken delivery of their new supercomputer, a 32 processor Apollo Odyssey distributed shared memory machine with a hierarchical communication subsystem. Valentine McKee's research advisor, Jack Swigert, has asked her to be…

题目: BIT has recently taken delivery of their new supercomputer, a 32 processor Apollo Odyssey distributed shared memory machine with a hierarchical communication subsystem. Valentine McKee's research advisor, Jack Swigert, has asked her to benchmark…

题意:有n个处理器,给出n*n的邻接矩阵的一半,表示相互之间传输信息的花费(另一半与给出的一半对称,即双向都可传输),x表示不能传输,问从第一个处理器传输到所有处理器的最小花费总和是多少. 就是跑一遍最短路,然后求和…… 原来我以前做的最短路都这么水…… #include<stdio.h> #include<string.h> #include<vector> #include<algorithm> #include<queue> using n…

题目链接:http://poj.org/problem?id=1502 Description BIT has recently taken delivery of their processor Apollo Odyssey distributed shared memory machine with a hierarchical communication subsystem. Valentine McKee's research advisor, Jack Swigert, has ask…

http://poj.org/problem?id=1502 刷一道模板题稳定一下心情... Dijkstra求单源最短路,就是输入的时候注意下,是按下三角输入的(无向图),输入字符x表示i与j不通. 可以这样输入: if(scanf("%d",&w)) map[i][j] = map[j][i] = w; else scanf("x"); #include<stdio.h> #include<string.h> const int…

题目大意: BIT最近要取会他们的超级计算机,32处理器阿波罗奥德赛与分层通信子系统分布式共享内存的机器(听着很高端大气),瓦伦丁*麦基的顾问杰克*斯威特告诉她基准测试的新系统.(没有明白什么意思) “因为阿波罗是一个分布的共享内存的机器,内存的访问和交流通信的时间是不统一的”瓦伦丁告诉斯威特......(受不了了,这什么破英语,又臭又长还对话!!!!) 直接说这道题的意思算求,就是给一个临街矩阵,这个邻接矩阵因为上三角跟下三角一样,所以只给了下三角,* 号代表两点不相连,然后求出来点1到达所有…

BIT has recently taken delivery of their new supercomputer, a 32 processor Apollo Odyssey distributed shared memory machine with a hierarchical communication subsystem. Valentine McKee's research advisor, Jack Swigert, has asked her to benchmark the…

题目大意:求点1到所有点最短路径的最大值 思路:水题,单源最短路,网上解题清一色dijkstra,但是点数小于100显然floyd更简洁嘛 #include<cstdio> #include<string.h> #define maxn 101 #define inf 100000 using namespace std; int read(){ int f=1,x=0;char ch=getchar(); while(ch<'0'||ch>'9'){if(ch=='x…

题目链接:https://vjudge.net/problem/POJ-1502 dijkstra板子题,题目提供下三角情况,不包含正对角线,因为有题意都为0,处理好输入,就是一个很水的题. #include <iostream> #include <cstring> #include <algorithm> #include <cstdio> #include <string> #include <vector> using nam…

题意 : 给出 N 个点,各个点之间的路径长度用给出的下三角矩阵表示,上上角矩阵和下三角矩阵是一样的,主对角线的元素都是 0 代表自己到达自己不用花费,现在问你从 1 到 N 的最短路,矩阵的 x 代表点间无法互相到达 分析 : 最短路模板…… 就是在输入的时候需要将字符串变成整数.自己写也可以,也可以使用 atoi(char *)函数,其作用是将字符串数组变成整数,复杂度为 O(n) #include<bits/stdc++.h> using namespace std; ; const i…

题目链接:http://poj.org/problem?id=1502 题意:一个处理器给n-1个处理器发送广播,问最短时间.广播时并发,也就是各个路径就大的一方.输入如果是x的话说明两个处理器不能相互通信.输入是矩阵的左三角. 题解:一个最短路的裸题吧.输入的时候注意一下字符的转换.floyd爆一遍之后再对每个路径找最大值即可. 代码: #include<cstdio> #include<cstdlib> #include<cstring> #include<i…

BIT has recently taken delivery of their new supercomputer, a 32 processor Apollo Odyssey distributed shared memory machine with a hierarchical communication subsystem. Valentine McKee's research advisor, Jack Swigert, has asked her to benchmark the…

题目链接:http://poj.org/problem?id=1502 题意是给你n个点,然后是以下三角的形式输入i j以及权值,x就不算 #include <iostream> #include <cstdio> #include <cstring> #include <queue> using namespace std; ; const int INF = 1e9; typedef pair <int , int> P; struct da…

题目大意: 给你 1到n ,  n个计算机进行数据传输, 问从1为起点传输到所有点的最短时间是多少, 其实就是算 1 到所有点的时间中最长的那个点. 然后是数据 给你一个n 代表有n个点, 然后给你一个邻接矩阵, 只有一半,另一半自己补 下面是练习的代码. 分别用了Floyd 和 Dijkstra 还有 Spfa(邻接矩阵版) #include <iostream> #include <cmath> #include <cstring> #include <cst…