//输入一组整数.求出这组数字子序列和中最大值 #include <stdio.h> int MAxSum(int arr[],int len) { int maxsum = 0; int i; int j; for (i = 0; i < len; i++) { int thissum = 0; for (j = i; j < len; j++) { thissum += arr[j]; if (thissum>maxsum) maxsum = thissum; } } r
总结::需要耐心,加思考.做事不思考,那就是白做徒劳!!!!! package com.aini; import java.util.Scanner; //操...为什么数组的大小比较我硬是搞不懂,比较大小依然放在for循环里... //从键盘输入一组数据,并输出最小值 //还有循环结构的括号不知道在哪里结束 public class erte { public static void main(String[] args) { Scanner c = new Scanner(System.in
A. Olympiad time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output The recent All-Berland Olympiad in Informatics featured n participants with each scoring a certain amount of points. As the head
function spreadingability=sir(A,beta,mu) for i=1:length(A) for N=1:50%随机次数 InitialState=zeros(length(A),1);InitialState(i)=1; time=5;%传播时间 I(N,:)=sire(A,InitialState,beta,mu,time); end spreadingability(i,1)=mean(mean(I));%节点i的传播能力 end end function I=
import java.util.Scanner; public class TestScanner { public static void main(String[] args) { Scanner scanner = new Scanner(System.in); System.out.print("Password: "); long password = scanner.nextLong(); long pwd = 0; long t1 = System.currentTim
