Given an integer n, count the total number of digit 1 appearing in all non-negative integers less than or equal to n. For example: Given n = 13, Return 6, because digit 1 occurred in the following numbers: 1, 10, 11, 12, 13. Hint: Beware of overflow.
1.为什么要学习切片[切片是解决何种问题的?] (2)对于含有元素很少的list,我们遍历其前三个元素,通常可以这样来实现: #遍历list,取其中索引为[0].[1].[2]的元素: L = ['Xiaoming','Xiaohong','Xiaolan','Xiaowang','Xiaozhang'] a = [L[0],L[1],L[2]] print(a)------------------------------------------------------------------