Tempter of the Bone Time Limit:1000MS Memory Limit:32768KB 64bit IO Format:%I64d & %I64u Description The doggie found a bone in an ancient maze, which fascinated him a lot. However, when he picked it up, the maze began to shake, and the doggi
Tempter of the Bone Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 92175 Accepted Submission(s): 25051 Problem Description The doggie found a bone in an ancient maze, which fascinated him a
<题目链接> 题目大意:一个迷宫,给定一个起点和终点,以及一些障碍物,所有的点走过一次后就不能再走(该点会下陷).现在问你,是否能从起点在时间恰好为t的时候走到终点. 解题分析:本题恰好要在某一时刻到达,所以需要用到可行性剪枝中的奇偶剪枝,如果在某一点,它所剩的步数与到终点的最短距离之差是偶数,说明这种情况有可能恰好在规定时刻到达终点,否则不可能,将其剪去. #include <bits/stdc++.h> using namespace std; ][]; ][]; int n,
Tempter of the Bone Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 146511 Accepted Submission(s): 39059 Problem Description The doggie found a bone in an ancient maze, which fascinated him
Tempter of the Bone Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 151082 Accepted Submission(s): 40265 Problem Description The doggie found a bone in an ancient maze, which fascinated him
传送门: http://acm.hdu.edu.cn/showproblem.php?pid=1010 Tempter of the Bone Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 144191 Accepted Submission(s): 38474 Problem Description The doggie fou
M - Tempter of the Bone Time Limit:1000MS Memory Limit:32768KB 64bit IO Format:%I64d & %I64u Description The doggie found a bone in an ancient maze, which fascinated him a lot. However, when he picked it up, the maze began to shake, and the d
如果所给的时间(步数) t 小于最短步数path,那么一定走不到. 若满足t>path.但是如果能在恰好 t 步的时候,走到出口处.那么(t-path)必须是二的倍数. 关于第二种方案的解释: 这种方案学名为“奇偶剪枝”.我们已知了最短的步数就是直角三角形的两条直角边,实际上的路径却不一定非要沿着这两条边走的.仔细看看只要是移动方向一直是右.下,那么走到的时候总步数也一定是path的.然而由于墙的存在或许我们不可能一直右.下的走下去.为了避开墙,我们可能会向左走,向上走等等.但为了到达目的地