1.查询表中重复数据.select * from peoplewhere peopleId in (select peopleId from people group by peopleId having count(peopleId) > 1)2.删除表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断,只留有rowid最小的记录delete from people where peopleId in (select peopleId
js中的NaN不和任何值相等,包括自身. 所以可以使用x!=x来判断x是否是NaN,当且仅当x为NaN时,表达式的结果为true. NaN != NaN //true 可以依此删除数组中的'NaN'. Array.prototype.delNaN = function () { var arr = []; for (var i = 0; i < this.length; i++) { if (this[i] === this[i]) { arr.push(this[i]); } } return
DECLARE @tablename VARCHAR(30),@sql VARCHAR(500)DECLARE cur_delete_table CURSOR READ_ONLY FORWARD_ONLY FORSELECT name FROM sysobjects WHERE name LIKE 'PUB%' AND type='U'OPEN cur_delete_tableFETCH NEXT FROM cur_delete_table INTO @tablenameWHILE @@FETC
有些时候,当一个表已经建好,并且已经使用后,发现需要对表结构进行修改,这个时候就要对表中的列进行增删查改操作. 为表增加新列: ALTER TABLE table_name ADD ( column_name [DEFAULT VALUE],.... ); 删除表中的列: ALTER TABLE table_name DROP COLUMN column_name; 查看表中的列: SELECT * FROM COLS WHERE TABLE_NAME='INCIDENTSM1' ORDER B
题目描述 在一个排序的链表中,存在重复的结点,请删除该链表中重复的结点,重复的结点不保留,返回链表头指针. 例如,链表1->2->3->3->4->4->5 处理后为 1->2->5 代码如下:未进行优化 public class ListNode { int val; ListNode next = null; ListNode(int val) { this.val = val; } } public class Solution { //将所有重复的结