题目要求: 将输入的大写字母转成对应小写的后5个,如A转换后为f:如果转换后大于z则从a重新计,即多出1就转成a,多出2就转成b以此类推. Java代码: ```java private static char exchange(char c) { if (c > 'Z' || c < 'A') { throw new RuntimeException("必须为26个大写字母中的一个"); } int begin = 'a', end = 'z', cur = Charac
1. 定义一个print_lol函数来控制列表的缩进和写入位置 import sys """this is a new fuction, which work for a list""" def print_lol(the_list,indent=False,level=0,where=sys.stdout): """ one arguement is the_list""" for e
using System; public partial class testref : System.Web.UI.Page { static void outTest(out int x, out int y) {//离开这个函数前,必须对x和y赋值,否则会报错. //y = x; //上面这行会报错,因为使用了out后,x和y都清空了,需要重新赋值,即使调用函数前赋过值也不行 x = ; y = ; } static void refTest(ref int x, ref int y) {
1. Print them to screen man = [] other = [] try: data = open('sketch.txt') for each_line in data: try: (role, line_spoken) = each_line.split(':',1) line_spoken=line_spoken.strip() if role== 'Man': man.append(line_spoken) elif role == 'Other Man': oth
取自<Focus On 3D Terrain Programming>中的一段: //-------------------------------------------------------------- // Name: CTERRAIN::FilterHeightBand - private // Description: Apply the erosion filter to an individual // band of height values // Arguments:
