select * from DB_PATCH awhere lower(a.db_name) in (select lower(db_name) from DB_PATCH group by lower(db_name) having count(*) > 1) delete from DB_PATCH awhere lower(a.db_name) in (select lower(db_name) from DB_PATCH group by lower(db_name) having co
1.在面试的时候碰到一个 问题,就是让写一张表中有id和name 两个字段,查询出name重复的所有数据,现在列下: select * from xi a where (a.username) in (select username from xi group by username having count(*) > 1) 2.查询出所有数据进行分组之后,和重复数据的重复次数的查询数据,先列下: select count(username) as '重复次数',username from
在A表中存在一个字段“AccountId”,而且不同记录之间的“AccountId”值有可能会相同,现在就是需要查询出在该表中的各记录之间,“AccountId”值存在重复的项,这里count记录该字段重复的记录数(此处只针对该字段是否重复进行查询):Select AccountId,Count(*) From A Group By AccountId Having Count(*) > 1 如果查询多个字段也相同大则如下:Select AccountId,Name,Count(*) From
比如现在有一人员表 (表名:peosons)若想将姓名.身份证号.住址这三个字段完全相同的记录查询出来 select p1.* from persons p1,persons p2 where p1.id<>p2.id and p1.cardid = p2.cardid and p1.pname = p2.pname and p1.address = p2.address 可以实现上述效果. 几个删除重复记录的SQL
1.表数据结构如下 select * from test t , 'jerry'); , 'jerry'); , 'jerry'); , 'tom'); , 'tom'); , 'jake'); , 'jake'); , 'jake'); 2.删除sql如下 a.name去重,取最小的字段 b.使用exists删除重复的数据 delete test a where not exists ( select * from (select min(id) id, name from test grou
例如表名为Course 需要查询出name重复的有那些??? 解答如下: 补充: 如:查询每个姓名出现大于2次,SQL如下 SELECT COUNT(NAME) as '出现次数', NAME FROM 表名GROUP BY NAME HAVING count(NAME) > 2 ORDER BY 出现次数 DESC
/* create view testview as SELECT subject,MIN(Id) as id FROM test GROUP BY subject; select * FROM test WHERE id not in (SELECT id FROM testview); */ mysql> select * from test; +----+------------+-------+-----------+ | id | name | score | subject | +-
今天在QQ群众讨论到一个问题,记录下下来,一边以后用的时候可以翻阅 总结除了三种方法 --方法1,,这一种方法不行,,错误的认识了,@@ROWCOUNT,,,唉,,学艺不精,,丢人啊 SELECT TOP 1 @@ROWCOUNT FROM dbo.tb_CommonDataDict --方法2if exists(SELECT TOP 1 * FROM dbo.tb_CommonDataDict )--方法3if (select Count(*) from a)>0
总结: 1.计算某列值(数值or字符串)重复的次数 select 列1,count( 列1 or *) count1 from table1 group by 列1 输出的表为:第一列是保留唯一值的列1,第二列是count1列的统计表. 问:那怎么把其他列信息也都显示出来呢?可以参考:http://www.myexception.cn/oracle-develop/1767413.html 我这里自己做一个总结,进入下一步.2.一张表中增加一列计算某列值重复的次数列,并且把表中其他列也显示出
1.查询表中重复数据.select * from peoplewhere peopleId in (select peopleId from people group by peopleId having count(peopleId) > 1)2.删除表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断,只留有rowid最小的记录delete from people where peopleId in (select peopleId
1.查找表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断 代码如下: select * from people where peopleId in (select peopleId from people group by peopleId having count (peopleId) ) 2.删除表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断,只留有rowid最小的记录 代码如下: delete from people where peopleId
.查找表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断 select*from people where peopleIdin (select peopleIdfrom peoplegroupby peopleIdhaving ) .删除表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断,只留有rowid最小的记录 deletefrom people where peopleIdin (select peopleIdfrom peoplegroupby pe
--复制另一个数据库中的某张表的结构及数据--select * from Test.dbo.TestTable(查询表中所有数据) --into [表名] 插入当前数据库新表,如果没有该表就创建 select * into TestCopy from Test.dbo.TestTable --只复制表结构(1!=1等价于1<>1,只要where后的为false就可以)--把查询出的数据插入到新表,如果没有数据就只是复制表结构了select * into TestCopy from Test.d
sql某一表中重复某一字段重复记录查询与处理 1.查询出重复记录 select 重复记录字段 form 数据表 group by houseno having count(重复记录字段)>1 2.重复记录只显示一条ID值最小或最大的记录 select id,* from 数据表 where houseno (select 重复记录字段 form 数据表 group by 重复记录 字段 having count(重复记录字段)>1 ) 这样把houseno重复的的ID值全部显示