题目描述: You're given strings J representing the types of stones that are jewels, and S representing the stones you have. Each character in S is a type of stone you have. You want to know how many of the stones you have are also jewels. The letters in
在有些题目中打印简单图形必须使用StringBuilder或者StringBuffer,否则会运行超时(用String都会超时). 因为在题目的要求中说到输入的n是小于1000的,用双重循环就会超时,用单层循环的String也会超时,因为+=的次数有点多了. 传说中的简单图形: Java代码如下: 主要用了substring方法和append import java.util.Scanner; public class Main{ public static void main(String [
为了让编译器更好地优化循环,应该尽量让循环中降低推断,方法之中的一个是将推断语句整合进表达式.还是这个样例: for (int i = 0; i < 1000*10; i++) { sum += data[i/1000][i%10]; } 假如我们须要加一个推断.仅仅有非负整数才须要作求和运算: for (int i = 0; i < 1000*10; i++) { if (data[i/1000][i%10] >= 0) sum += data[i/1000][i%10]; } 以下将
添加三个线程同时启动执行某一方法,并依次调用某方法中的打印输:ABC ABC ABC ABC 实现代码如下: using System; using System.Collections.Generic; using System.Linq; using System.Text; using System.Threading; using System.Threading.Tasks; namespace SuperMarket.Test { class Program { static voi