study from : https://www.cnblogs.com/reaptomorrow-flydream/p/9613847.html python 二维数组键盘输入 1 m = int(input())2 grid = [[] for i in range(m)]3 for i in range(m):4 line = input().split(' ')5 for j in range(len(line)):6 grid[i].append(int
<?php class DBDA { public $host = "localhost"; public $uid = "root"; public $pwd = "20982239"; //执行sql语句,返回相应的结果函数 //$sql是要执行的sql语句 //$type是sql语句的类型,0代表增删改,1代表查询 //$db代表要操作的数据库 public function Query($sql,$type=1,$db="
Given a 2D board and a word, find if the word exists in the grid. The word can be constructed from letters of sequentially adjacent cell, where "adjacent" cells are those horizontally or vertically neighboring. The same letter cell may not be us
一维数组: arr = input("") //输入一个一维数组,每个数之间使空格隔开 num = [int(n) for n in arr.split()] //将输入每个数以空格键隔开做成数组 print(num) //打印数组 一维数组输入输出示例: 二维数组: (以n*n的二维数组为例) n = int(input()) //输入二维数组的行数和列数 line = [[0]*n]*n //初始化二维数组 for i in range(n): line[i] = inpu
// 二维数组中的查找,杨氏矩阵在一个二维数组中.每行都依照从左到右的递增的顺序排序. // 每列都依照从上到下递增的顺序排序.请完毕一个函数,输入这种一个数组和一个数.推断数组中是否包括这个数 #include <stdio.h> #define col 4 #define rol 4 int yang(int(*p)[col], int num) { int i = 0; int j = col - 1; while (j+1) { int *q = &(p[i][j]); if