As we all know that long2ip works as ip1.ip2.ip3.ip4 (123.131.231.212) long ip => (ip1 * 256 * 256 * 256) + (ip2 * 256 * 256) + (ip3 * 256) + ip4 2072242132 => (123 * 256 * 256 * 256) + (131 * 256 * 256) + (231 * 256) + 212 But what would be pseudo
如何将字符串中的10进制数和16进制数提取出来,看以下代码: #include <stdio.h> typedef char TUINT8 ; typedef int TUINT32; TUINT32 Read_DecNumber(const TUINT8* str); TUINT32 Read_HexNumber(const TUINT8* str); int main(void) { int ret = Read_DecNumber("1000"); int d = R
package com.swift;//所属包 import java.util.Scanner;//导入扫描器 public class Hex2Decimal { public static void main(String[] args) { Scanner scan = new Scanner(System.in); System.out.println("please enter a Hex:"); String hex = scan.nextLine();//读取一行 he
// 将时间戳转换成日期格式: function timestampToTime(timestamp) { var date = new Date(timestamp);//时间戳为10位需*1000,时间戳为13位的话不需乘1000 var Y = date.getFullYear() + '年'; var M = (date.getMonth()+1 < 10 ? '0'+(date.getMonth()+1) : date.getMonth()+1) + '月'; var D = (dat
java转换成秒数 Date类有一个getTime()可以换回秒数,例如: public class DateToSecond { public static void main(String[] args) { Date date = new Date(System.currentTimeMillis()); System.out.println(date.getTime()); } } 或者直接使用long类型存储毫秒数, long base = System.currentTimeMill