才疏学浅,智商不够,花了一晚上看了二叉树.记录一下: 1.二叉树的遍历 前序遍历:根节点->左子树->右子树 中序遍历:左子树->根节点->右子树 后序遍历:左子树->右子树->根节点 三层二叉树: A ↙ ↘ B C ↙ ↘ ↙ ↘ D E F G前序:先把BDE,CFG看做是A的左右子节点,因此是从A开始读,A作为第一个,然后进到左子节点 BDE, 这时再把它看
Given a binary tree, find all leaves and then remove those leaves. Then repeat the previous steps until the tree is empty. Example: Given binary tree 1 / \ 2 3 / \ 4 5 Returns [4, 5, 3], [2], [1]. Explanation: 1. Remove the leaves [4, 5, 3] from the
Given a binary tree, find all leaves and then remove those leaves. Then repeat the previous steps until the tree is empty. Example:Given binary tree 1 / \ 2 3 / \ 4 5 Returns [4, 5, 3], [2], [1]. Explanation: 1. Remove the leaves [4, 5, 3] from the t
二叉树知识参考:深入学习二叉树(一) 二叉树基础 递归实现层次遍历算法参考:[面经]用递归方法对二叉树进行层次遍历 && 二叉树深度 上面第一篇基础写得不错,不了解二叉树的值得一看. 用递归来实现二叉树的层次遍历.lua实现 先上代码: function FindTree(tree, callback) local function Find(tree, level) ) then return false; end ) then if callback then callback(tre
节点数据结构 class TreeNode { TreeNode left = null; TreeNode right = null; } 最大深度,基本思路是:使用递归,分别求出左子树的深度.右子树的深度,两个深度的较大值+1就是最大深度. // 获取最大深度 public static int getMaxDepth(TreeNode treeNode) { if (treeNode == null) return 0; else { int left = getMaxDepth(tree
03-树1. List Leaves (25) Given a tree, you are supposed to list all the leaves in the order of top down, and left to right. Input Specification: Each input file contains one test case. For each case, the first line gives a positive integer N (<=10) wh