Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST. 这道题是要求把有序链表转为二叉搜索树,和之前那道Convert Sorted Array to Binary Search Tree 将有序数组转为二叉搜索树思路完全一样,只不过是操作的数据类型有所差别,一个是数组,一个是链表.数组方便就方便在可以通过index直接访问任意一个元
Given n, generate all structurally unique BST's (binary search trees) that store values 1...n. For example,Given n = 3, your program should return all 5 unique BST's shown below. 1 3 3 2 1 \ / / / \ \ 3 2 1 1 3 2 / / \ \ 2 1 2 3 confused what "{1,#,2
03-树1. List Leaves (25) Given a tree, you are supposed to list all the leaves in the order of top down, and left to right. Input Specification: Each input file contains one test case. For each case, the first line gives a positive integer N (<=10) wh
/****************************************************************** 题目: The order of a Tree(hdu 3999) 链接: http://acm.hdu.edu.cn/showproblem.php?pid=3999 题意: 给你一个序列建立一棵二叉搜索树 要你找出另外一个序 列,可以建立和原序列建立的二叉搜索树一样且这个序列 是字典序最小 算法: 二叉搜索树 思想: 对于一个二叉搜索树,它的先序遍历是能建立
http://acm.hdu.edu.cn/showproblem.php?pid=3791 用数组建立二叉树: 二叉搜索树 Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 2354 Accepted Submission(s): 1016 Problem Description 判断两序列是否为同一二叉搜索树序列 Input