先看错误信息: java.sql.SQLException: Before start of result set at com.mysql.jdbc.SQLError.createSQLException(SQLError.java:910) at com.mysql.jdbc.ResultSet.checkRowPos(ResultSet.java:720) at com.mysql.jdbc.ResultSet.getStringInternal(ResultSet.java:5624)
public boolean tabIsExist(String tabName){ boolean result = false; if(tabName == null){ return false; } Cursor cursor = null; try { String sql = "select count(*) as c from sqlite_master where type ='table' and name ='"+tabName.trim()+"' &qu
SQL 如下: sql 1. SELECT X.USER_ID, X.TOTAL_NO, X.ORDER_NO, X.ORDER_NO / X.TOTAL_NO AS PERCENTAGE_NO AS ORDER_NO, @rowCount AS TOTAL_NO, USER_ID ) b, (SELECT @rowCount := ( SELECT COUNT(*) FROM T_SD_USER ) ) c ORDER BY USER_ID DESC ) X sql2. ) AS PERCEN
jmeter判断数据库中是否存在相应记录可以使用count 配合case,然后再加个断言,后面用 变量JMeterThread.last_sample_ok来判断是否存在相应记录 select case count(1) when 1 then 'true' else 'false' end FROM gringotts.t_user where id = 18239391
package com.lanxi.demo2; import java.util.HashSet; import java.util.Iterator; import java.util.Set; public class Test { public static void main(String[] args) { //引用一个Set集合实现类 Set set=new HashSet(); //添加单个元素 set.add("哈"); set.add("士");
在mysql数据库中,null是一个经常出现的情况,关于mysql中的null,有哪些注意事项呢?下面简单总结归纳下,后续会不断补充. 1. is null 首先判断数据库中某一列的值是否为null,不能用等于来判断,必须使用 is.比如,select * from users where user_name is null 或者 select * from users where user_name is not null,而不能是 select * from users where use
需求:1.客户提供的excel表和数据库中的表结构总是有一些差距,id的生成,各种字段的关联等等 2. 如何在Excel中生成Guid. 1.在Excel的宏中执行以下代码: Private Declare PtrSafe Function CoCreateGuid Lib "ole32" (id As Any) As Long Private Function CreateGUID() As String Dim id(0 To 15) As Byte Dim Cnt As Long