问题 你想把一个昂贵的属性移到另一个实体,这样你就可以延迟加载当前这个实体.对于一个加载昂贵的而且很少用到的属性尤其有用. 解决方案 模型和上一节(Recipes 13-7)的一致,如Figure13-10所示 Figure 13-10. A model with a Resume entity with a Body property that contains the entire text of the applicant’s resume. In this recipe, we’ll m
Given a string which contains only lowercase letters, remove duplicate letters so that every letter appear once and only once. You must make sure your result is the smallest in lexicographical order among all possible results. Example: Given "bcabc&q
Remove the minimum number of invalid parentheses in order to make the input string valid. Return all possible results. Note: The input string may contain letters other than the parentheses ( and ). Examples: "()())()" -> ["()()()",
Remove all elements from a linked list of integers that have value val. Example Given: 1 --> 2 --> 6 --> 3 --> 4 --> 5 --> 6, val = 6 Return: 1 --> 2 --> 3 --> 4 --> 5 Credits:Special thanks to @mithmatt for adding this probl
Given a sorted linked list, delete all duplicates such that each element appear only once. For example,Given 1->1->2, return 1->2.Given 1->1->2->3->3, return 1->2->3. 移除有序链表中的重复项需要定义个指针指向该链表的第一个元素,然后第一个元素和第二个元素比较,如果重复了,则删掉第二个元素,
Given an array and a value, remove all instances of that value in place and return the new length. The order of elements can be changed. It doesn't matter what you leave beyond the new length. 这道题让我们移除一个数组中和给定值相同的数字,并返回新的数组的长度.是一道比较容易的题,我们只需要一个变量用来计数
Given a linked list, remove the nth node from the end of list and return its head. For example, Given linked list: 1->2->3->4->5, and n = 2. After removing the second node from the end, the linked list becomes 1->2->3->5. Note: Given
This is come from http://blog.lyhdev.com/2013/01/ubuntu-linux-apt-get.html 在 Ubuntu 下移除某個軟體套件,使用的指令是 apt-get remove,例如: sudo apt-get remove texlive-full但由於先前安裝此套件,會一併自動安裝相依套件(dependencies),所以需要再用 autoremove 清理. sudo apt-get autoremove或是在 rem
